🚀 go-pugleaf

On 20 Mar 1995 son3776@utdallas.edu wrote:

> Considering that we can't detect any such curvature in spacetime because
> we ourselves are affected by the same curvature to such an extent that if
> we travel with a relative velocity of zero in relation to the drawn
> circle there won't be any noticeable distortions, we will measure pi (to
> a degree of accuracy).

You keep saying this, and I keep telling you it's wrong, and I haven't
heard you respond yet.  The claim you make is:

   "We don't notice the spacetime curvature because we 'curve' with it"

and that is *false*.  Flat-out false.  If you make a large circle
(defined as "a locus of points all of which are measured to be
equidistant from a common point") deep in outer space and then

   (a)  Measure the distance around the circle
   (b)  Measure the distance across the circle
   (c)  Divide (a) by (b)

You.  Will.  Not.  Get.  Pi.

> --
> "Somewhere else the tea's getting cold." -- The Doctor
>
>

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 | Michael Weiss           |                                              |
 | email: mkw21@cam.ac.uk  |            "Got my mojo working!"            |
 | Darwin College          |                   -- Muddy Waters            |
 | Cambridge CB3 9EU       |                                              |
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