Re: Pore Size & MWCO

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Article #2319

#2319

From: David Resnick
Date: Mon, 09 Oct 1995 00:00

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lhom@OCF.Berkeley.EDU (Louis Hom) wrote:
>I found some dialysis tubing with an average pore radius of 24 angstroms.
>Is there a convenient way to convert this to an approximate MWCO?  
>-- 


Well, if you assume your protein is spherical....

For a sphere of radius 1.2x10-9 meters, volume = (4/3) x Pi x r^3 = 
	7.23x10^-27 meters^3

Average protein density = .73 g/ml = 7.3x10^5 g/meter^3

Mass of protein = 7.3x10^5 x 7.23x10^-27 = 5.28x10^-21 g/molecule
                         
MW of protein = 5.28x10^-21x6.02x10^23 molecules/mole = 3177 g/mole

So it looks like the answer is ~ 3 kDa.  I just threw this together, you might want to check my math, but the basic idea is correct.  

-David

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From: David Resnick <dresnick@athena.mit.edu>
Subject: Re: Pore Size & MWCO
Date: 1995/10/09
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