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Article #2797

Re: What's the overall ratio?

#2797
From: Larry Loen
Date: Tue, 05 Jan 1993 19:46
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In article <9301051753.AA21758@TIS.COM>, mjr@TIS.COM (Marcus J. Ranum) writes:
|> 
|> 	This is probably a naive question, but..
|> 
|> 	When designing cryptosystems I'd imagine it's desireable to use
|> algorithms that don't parallelize well. Is it feasible to somehow add
|> a step to a process like exponentiation that won't decompose well? Lenstra's
|> experiment with using loads of machines to factor primes shows us that
|> massively parallel attacks are just a matter of networking. ;) Is there
|> anything like factorization that also has the property of not parallelizing
|> well or at all?
|> 
|> mjr.

Interesting idea.  But, I wonder if it matters as much as it seems.  All
that seems necessary is to have a certain amount of sequentiality built-in
to the attack process.  Something as simple as doing a multiply followed by
a compare probably does not "parallelize" particularly well, particularly
if the whole result is needed for some later step in the process.

One always has the choice of implementing the whole algorithm (whether it
is prime factoring or DES key exhaustion or whatever) on a single chip and
building as many of these as one wishes, accepting the delay of some number
of sequential steps, N.  N will almost certainly be proportional to the
time of encryption of a single step, which must by definition be affordable.
One overcomes the fact that the N steps must be performed (say) 2 to the 54
times for the attack to succeed by building lots of chips.

At some point, it becomes cheaper to buy more of a particular chip with N
steps than to try and combine a few of the remaining steps and build an 
instrinsically faster chip with, say, N-5 steps by trying to combine various 
adjacent steps in a single joint step.  Offhand, I'd say that DES
is hard to parallelize past the point of doing a single "round" in parallel.
Perhaps it can now be done, but I can easily imagine the hardware to do, say,
two DES steps at once being nearly the square of the amount of hardware to
do one round.  If so, it is net cheaper (and, as fast in the long run) to
simply buy more of the chips that take time unit N.

Likewise, for factoring, one could imagine a similar combinatoric explosion
if one tried to do certain multiplication and division steps in a single
hardware "step".  The "N" cost of a step may be a little higher or lower
than RSA encryption, per se (I don't know, offhand), but it must surely be
the number of times the factoring process is run, not the time unit N for
a given attempt, that makes the problem intractable with known methods.

I have trouble imagining a case where an encryption process does not produce
an affordable unit "N" that will not be able be attacked in this manner.
That is, the base algorithm, if it is affordable, will be able to be the
minimum time unit (or, proportional to some usable equivalent) to be a useful
departure point for parallelism.

-- 
   Larry W. Loen        |  My Opinions are decidedly my own, so please
                        |  do not attribute them to my employer
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From: lwloen@rchland.vnet.ibm.com (Larry Loen)
Subject: Re: What's the overall ratio?
Sender: news@rchland.ibm.com
Message-ID: <1993Jan05.194654.10849@rchland.ibm.com>
Date: Tue, 05 Jan 1993 19:46:54 GMT
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Disclaimer: This posting represents the poster's views, not necessarily those of IBM
References: <cfG9faf0Bwwb4F5T9z@transarc.com> <1993Jan05.160811.29681@rchland.ibm.com> <1icec7INNo3h@uwm.edu> <9301051753.AA21758@TIS.COM>
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