🚀 go-pugleaf

z and y solved:


// y = y + (z << 4 ^ z >> 5) + z ^ _sum + k[ _sum & 3 ]; // 4446306

 y = y + ((z << 4) ^ (z >> 5)) + z ^ (_sum + k[ _sum & 3 ]);  // solved

  _sum = _sum + delta;

// z = z + (y << 4 ^ y >> 5) + y ^ _sum + k[ _sum >> 11 & 3]; // 2585699276
 z = z + ( (y << 4) ^ (y >> 5) ) + y ^ (_sum + k[ (_sum >> 11) & 3]); //
solved

Now the question remains if it is supposed to happen like this.

I am starting to doubt you guys know what you doing :)

You might want to use things like (  )

Which every mathcians should use to be absolutely clear about operator
precedence.





<disastry@saiknes.lv.NO.SPaM.NET> wrote in message
news:3D69F6F6.E43591E6@saiknes.lv.NO.SPaM.NET...
> -----BEGIN PGP SIGNED MESSAGE-----
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>
> skybuck wrote:
> > The problems are probably with these lines of code:
> >
> > c version:
> >
> > y += (z<<4)+a ^ z+sum ^ (z>>5)+b;
> > z += (y<<4)+c ^ y+sum ^ (y>>5)+d;
> >
> > pascal version:
> >
> > y := y + (z shl 4) + a xor z + _sum xor (z shr 5) + b;
> > z := z + (y shl 4) + c xor y + _sum xor (y shr 5) + d;
>
> 1) try:
>   y := y + ((z shl 4) + a xor z + _sum xor (z shr 5) + b);
> or even
>   y := y + (((z shl 4) + a) xor (z + _sum) xor ((z shr 5) + b));
>
> 2) better use XTEA (aka (TEAN)
>
> __
> Disastry  http://disastry.dhs.org/
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