Article View: sci.electronics.basics
Article #53Re: phasors and power calcs
From: Don Kelly
Date: Sun, 29 May 2005 03:46
Date: Sun, 29 May 2005 03:46
51 lines
2831 bytes
2831 bytes
"Ed-" <eddie_nospam@optusnet.com.au> wrote in message news:4297f96e$0$1228$afc38c87@news.optusnet.com.au... > next question: > how can i get the electric meter to turn backwards by using some caps? You can't. Capacitors will change the power factor but not the real power(*time) which the meter measures. Changing the pf will result in less current and some decrease in losses. If you have demand metering, then the demand may be reduced. -- Don Kelly dhky@peeshaw.ca remove the urine to answer > > > <jan@janhurst.com> wrote in message > news:42948abb$0$28838$5a62ac22@per-qv1-newsreader-01.iinet.net.au... > : Hello, > : > : I am studying an introductory electronics course and have been given > the > : following problem: > : > : A small factory has the following loads operating from the 240Vrms > 50Hz > : supply > : a) Forty 50 watts incandescent lamps with unity power factor > : b) Thirty-five 40 watts fluorescent lamps with a lagging power factor > of 0.9 > : c) One 2400 watts air conditioning system with a lagging power factor > of > : 0.65. > : > : I am asked to draw the complete phasor diagram and determine the total > : peak current drawn and overall power factor of the factory. > : > : I'm a little stuck :( I have some phasor diagrams put together which I > : am a little unsure of, but I don't really know how to determine peak > : current from this, can anyone shed some light or point me in the > : direction of some material to explain this sort of problem? I've been > : digging through a number of text books and am not really progressing. > : > : Thank you > : > : Jan >
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X-Google-Thread: 111d0a,f6267b6883c0c47a X-Google-Thread: 103407,f6267b6883c0c47a X-Google-Attributes: gid111d0a,gid103407,public X-Google-Language: ENGLISH,ASCII-7-bit Path: arc1-ca.pugleaf.net!g2news1.google.com!news4.google.com!news.glorb.com!news-out.newsfeeds.com!propagator3-LAX.newsfeeds.com!news-in.usenet.com!pd7cy1no!shaw.ca!pd7tw1no.POSTED!53ab2750!not-for-mail X-Trace-PostClient-IP: 70.66.146.62 Reply-To: "Don Kelly" <dhky@peeshaw.ca> From: "Don Kelly" <dhky@peeshaw.ca> Newsgroups: sci.electronics.basics,aus.electronics References: <42948abb$0$28838$5a62ac22@per-qv1-newsreader-01.iinet.net.au> <4297f96e$0$1228$afc38c87@news.optusnet.com.au> Subject: Re: phasors and power calcs Lines: 53 X-Priority: 3 X-MSMail-Priority: Normal X-Newsreader: Microsoft Outlook Express 6.00.2800.1437 X-MIMEOLE: Produced By Microsoft MimeOLE V6.00.2800.1441 Message-ID: <sWame.1507134$8l.1485328@pd7tw1no> Date: Sun, 29 May 2005 03:46:32 GMT NNTP-Posting-Host: 24.64.223.206 X-Complaints-To: abuse@shaw.ca X-Trace: pd7tw1no 1117338392 24.64.223.206 (Sat, 28 May 2005 21:46:32 MDT) NNTP-Posting-Date: Sat, 28 May 2005 21:46:32 MDT Organization: Shaw Residential Internet