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Article #154

Re: Best way to power array of LEDs?

#154
From: Tom Del Rosso
Date: Tue, 05 Nov 2002 05:35
39 lines
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"Bob Wilson" <rfwilson@intergate.nospam.bc.ca> wrote in
message news:useffdcqh8hne7@corp.supernews.com...
>
> Turning on the radio does not magically make the engine more efficient
so
> clearly what you are doing is to add load to the alternator (in order
to
> power the radio), and hence you the engine has to work a little harder
(and
> consume more gas) to do the extra work.
>
> What if your alternator was capable of somehow outputting a megawatt?
> Suddenly switching on a load that is using FAR more energy than it
takes to
> drive the car, would be an extreme example of this. If the answer to
your
> question was that you are dissipating less heat and burning no more
gas,
> then your engine would be running so efficiently that it would be
getting
> very cold, VERY fast!


If the alternator could supply a megawatt, then I'd expect it to be a
bigger mechanical load than the drive train even with no electrical
load.  When *less* current is drawn, does that mechanical load change
proportionately, or does the alternator, to some extent at least,
convert some of its unused capacity to more internal heat?


> Bottom line: you don't get something for nothing.

Well I wasn't thinking of getting something for nothing.  I was thinking
that it sounds too ideal for an increased load on the alternator to
convert into an exactly proportionate load increase on the engine.  If I
draw less power than the alternator can supply, isn't it just wasting
some of that power because of the non-ideal properties of the
alternator?  In other words does a generator precisely convert a higher
load current into more mechanical resistance?
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From: "Tom Del Rosso" <please-no.spam.tdnews@att.net>
Newsgroups: sci.electronics.components,sci.electronics.design,alt.engineering.electrical,aus.electronics,sci.electronics.repair
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Subject: Re: Best way to power array of LEDs?
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