🚀 go-pugleaf

In <1992Nov3.220234.23476@u.washington.edu> whit@carson.u.washington.edu (John Whitmore) writes:

>In article <davej.40.0@gmuvax2.gmu.edu> davej@gmuvax2.gmu.edu (David F. Juraschek) writes:
>>This is probably a very beat up old horse, but does anyone have a 
>>simple circuit they could post for an automobile headlight reminder
>>circuit? 

>	The standard trick is to connect from the switched +12V
>on the instrument panel to the (+) lead of the headlamps; if
>the headlamp terminal is more positive than the switched +12,
>a buzzer (low-current type, connected in series with a diode)
>goes off.  The buzzer has to be a low-current type because the
>current it draws is set by the quiescent draw of the instrument
>panel, which is the current sink for the circuit.

>	Auto shops often sell a small kit for this purpose,
>complete with fuse-block connectors and instructions.

>	John Whitmore

A better solution is to go from the +12 Switched sidelight feed, via a
buzzer to the drivers door light switch, you then need to put a diode in the
door circuit to stop the other doors operating the buzzer.

         +12v  (sidelights)
          |
        +----+
        |    | Buzzer (12v)
        +----+
          |
          +-------|<|-------- To existing drivers interior light switch
          |       Diode
          |
          O
         ----|  Drivers door switch
          O
          |
         Car Chassis

Thus when you leave your lights on *AND* open the drivers door, the buzzer
sounds.  If you mean to leave your lights on, just shut the door and the
buzzer stops!

Paul Simmonds  (ps@jet.uk)


- Disclaimer: Please note that the above is a personal view and should not 
  be construed as an official comment from the JET project.