🚀 go-pugleaf

In article <1991Jun15.023737.2673@mccc.edu> pjh@mccc.edu (Peter J. Holsberg) writes:
>I have a 10 ohm 10 watt resistor connected to the terminals of a 7.2V
>1000maH camcorder battery and the terminal voltage refuses to go below
>about 2.2V.  Is this sufficiently low to be considered a full-discharge?
>If not, how can I drop the voltage even further.
>
Keep at it. Unless you COMPLETELY kill it it will still retain memory.
You are probably at a charge region where some crystals inside are 
breaking down, at about the same quantum electric level. 
A friend of mine came up with an excellent way to completely
drain these things. :
Get 10 1157 dual element car light bulbs. Wire all 20 filaments in
parallel. Then, hook up heavy lead wire (try 10g or so) to appropriate
connectors to go to the battery. 
The neat thing about this is that the bulbs act like variable
resistors. As the voltage across them decreases, the power decreases,
the bulb cools down. The resistance of the elements then decreases, so
the bulb still draws near the same current (loosely) Bulbs such as
1157's range from about .45 ohms cold to about 2.5 ohms hot. They 
will also have no problem dissapating power (they can't burn up).
I think .045 ohms at a limit will have no problem in completely
killing the battery!
Regards,
Gordon.


-- 
WATERS,CLYDE GORDON-Georgia Institute of Technology Atlanta Ga 30332 
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