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Article #20284Re: Voltage and Amps Question (Huh?)
From: doug
Date: Thu, 29 Dec 1988 16:25
Date: Thu, 29 Dec 1988 16:25
30 lines
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1808 bytes
Ohms Law: V = IZ
2 2
Power Law: E = IV = I R = E / R
First, the current is indeed determined by Ohm's law. The problem is that a
car starter does not have a constant impedance. When the starter is turning
over quickly (low load, as in a warm day) the current draw is only 10->20
amps. On a cold day the starter has to work much harder and will often draw
100 or more amps. Note that all this is directly related to the work
(force x distance) the starter must do. So on a warm day the starter is
using between 120 and 240 watts energy and on a cold day upward of 1.2 Kw.
In general for power reasons it is better to have high voltage and low current
in a line. This is because the primary power loss is due to resistive voltage
drop in the line and is directly proportional to the current. You can beat
this by lowering the current (therefore raising the voltage) or lowering the
resistance (e.g. using superconductors). That's why power companies transmit
power cross country at hundreds of thousands of volts and do local power at
several thousand volts.
Douglas Rand
Internet: doug@zaphod.prime.com
Usenet: primerd!zaphod!doug
Phone: (508) - 879 - 2960
Mail: Prime Computer, 500 Old Conn Path, MS10C-17, Framingham, Ma 01701
-> The above opinions are mine alone.
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Path: arc1-ca.pugleaf.net!utzoo!utgpu!watmath!clyde!att!osu-cis!tut.cis.ohio-state.edu!bloom-beacon!primerd!zaphod!doug From: doug@zaphod.prime.com Newsgroups: sci.electronics Subject: Re: Voltage and Amps Question (Huh?) Message-ID: <44900003@zaphod> Date: 29 Dec 88 16:25:00 GMT References: <3415@ucdavis.ucdavis.edu> Lines: 30 Nf-ID: #R:ucdavis.ucdavis.edu:-341500:zaphod:44900003:000:1338 Nf-From: zaphod.prime.com!doug Dec 29 11:25:00 1988