Article View: sci.electronics
Article #9452Re: Need info on a diode rectifier
From: Doug Claar
Date: Thu, 10 Jan 1991 20:29
Date: Thu, 10 Jan 1991 20:29
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1402 bytes
/ hpcuhc:sci.electronics / ifar355@ccwf.cc.utexas.edu (David H. Huang) / 12:43 pm Jan 8, 1991 /
a) 1____|\|____2
| |/| |
--- ---
^ ^
/_\ /_\
| |
3____|\|____4
|/|
----------
Now would you like to know where the wires go?
1 & 4 = AC
2 = +
3 = -
Theory: A diode passes postive voltage thru the arrow, negative
into the arrow. (Ok, it's not real precise, but...)
So when 1 is positive, it goes to 2, but can't get to 3.
When it is negative, it goes to 3, but can't get to 2.
The same is true for 4: Positve goes to 2, negative to 3.
I'm sure that someone will say it much more eloquently, but that's
the terms in which my EE-wannabe CS mind remembers it.
Doug Claar
HP Computer Systems Division
UUCP: mcvax!decvax!hplabs!hpda!dclaar -or- ucbvax!hpda!dclaar
ARPA: dclaar%hpda@hplabs.HP.COM
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Path: arc1-ca.pugleaf.net!utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!samsung!dali.cs.montana.edu!uakari.primate.wisc.edu!zaphod.mps.ohio-state.edu!sdd.hp.com!hplabs!hpda!hpcuhc!dclaar From: dclaar@hpcuhc.cup.hp.com (Doug Claar) Newsgroups: sci.electronics Subject: Re: Need info on a diode rectifier Message-ID: <107710002@hpcuhc.cup.hp.com> Date: 10 Jan 91 20:29:32 GMT References: <42276@ut-emx.uucp> Organization: Hewlett Packard, Cupertino Lines: 29