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Article #9554Re: 80386.
From: Scott Linn
Date: Tue, 15 Jan 1991 18:44
Date: Tue, 15 Jan 1991 18:44
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/ hpcvca:sci.electronics / dana@locus.com (Dana H. Myers) / 12:51 pm Jan 14, 1991 / >Power is given by: > > P=IV > > Where: > P = power in Watts > I = current in Amperes > V = voltage in Volts Right, and I = C * dv/dt, so P = C * V * dv/dt. In CMOS dv is equal to the supply (transitions are from supply to ground), so P = C * V^2 / dt. But, 1/dt is the same as switching frequency, so Pdynamic = C * V^2 * f, not > Pdynamic = V^2 * 2 * Pi * f * C, which gives you a value over 6 times larger than the actual power dissipation. Scott Linn
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arc1-ca.pugleaf.net!utzoo!censor!geac!torsqnt!lethe!yunexus!ists!helios.physics.utoronto.ca!news-server.csri.toronto.edu!cs.utexas.edu!wuarchive!sdd.hp.com!hp-pcd!hpcvca!scottReferences:
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Path: arc1-ca.pugleaf.net!utzoo!censor!geac!torsqnt!lethe!yunexus!ists!helios.physics.utoronto.ca!news-server.csri.toronto.edu!cs.utexas.edu!wuarchive!sdd.hp.com!hp-pcd!hpcvca!scott From: scott@hpcvca.CV.HP.COM (Scott Linn) Newsgroups: sci.electronics Subject: Re: 80386. Message-ID: <3340012@hpcvca.CV.HP.COM> Date: 15 Jan 91 18:44:24 GMT References: <1990Dec28.210731.10685@zoo.toronto.edu> Organization: Hewlett-Packard Co., Corvallis, Oregon Lines: 23