🚀 go-pugleaf

In article <noringCD1n91.Lsv@netcom.com>, noring@netcom.com (Jon Noring) writes:
|> Hello,
|> I'm planning to produce a 16000x12000x256 GIF image of my favorite fractal
...
|> Jon Noring
|>
|> BTW, here's the *.par file for the overall image that I intend to do at
|> 16000x12000x256:
|> 
|> 
|> blkhole1           {
|>   reset=1720 type=mandel passes=1
|>   corners=-0.749888156/-0.749815747/0.0251925476/0.0252468362
|>   maxiter=32767
|>   colors=CCCzzy<9>000<14>c00b10<29>2xT0zU0za<2>0zy<15>00y<7>z0y<6>z00<15>z\
|>   z0<7>0z0<6>0zy<16>00y<7>z0y<5>z0800T<46>00T00T00V<13>00y<3>0zT<3>zU0zN6<\
|>   2>z0T<3>000665<8>zzy<9>zzy
|>   }
...

I took a look at this last night.  I just zoomed in to where my printed
copy of your post indicated, using the chroma colors.   Nice.  However, 
with the 32k iteration limit, the center was an unsightly black splotch.
Using unlimited iterations, this area acually has mush detail which your
16000x12000 image should show.  I wonder if a special program should be 
written to produce these special pictures.  I used log color scaling so 
things were not too messed up in this high iteration zone.

Jay
-- 
{ hilljr@jupiter.saic.com } begin writeln(3*ln(640320)/sqrt(163):17:15) end.
void main(){double sqrt(), y=1/sqrt(2.), a=.5, m=1,z; int n=0;
for(;m*=2,z=sqrt(1-y*y),y=(1-z)/(1+z),a=a*(1+y)*(1+y)-m*y,n<4;n++);
printf("%17.15lf\n",1/a);}