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2 total messages Started by Bart Killam Tue, 06 Oct 1992 19:59
Question on Young's Equation
#46
Author: Bart Killam
Date: Tue, 06 Oct 1992 19:59
61 lines
2645 bytes
I am having a problem understanding Young's
equation, an equation relating the connecting
angle of an air-water interface (in a air-water-
solid interace) with the interfacial tensions.
The equations seems counter-intuitive, and seems
to violate the principle of least action.

I am reviewing a text (Quantitative Hydrogeology, 
de Marsily) that discusses wetting/non-wetting
fluids in a air-water-solid interface. In a 
diagram (Fig. 2.12, p 28) of the interface, the
solid boundary is horizonal, with the water forming
a droplet on top. This is probably a common diagram
shown in any soil physics or physical chemistry text. 

The angle of the air-water interface is measured 
through the water. If the angle < 90 deg. the fluid
is "wetting". This is easy to see; as the angle 
approaches 0 deg., the drop spreads out over the
entire surface. Similarly, if the angle > 90 deg. 
the fluid is "non-wetting". As the angle approaches
180 deg., the droplet beads up to where only a point
is touching the solid. Again, easy to visualize.

 However:

 Young's Equation:


   cos(theta)= (sigma_s_a - sigma_s_w)/sigma_a_w

where  

  theta = the connecting angle

  sigma_s_a = interfacial energy between the solid-air
              (the energy required to separate a unit
               area of air-solid interface)

  sigma_s_w = interfacial energy between the solid-water

  sigma_a_w = interfacial energy between the air-water

Suppose (using J/m**2 or any convenient units)

  sigma_s_a = 1, sigma_s_w = 2 , sigma_a_w = 1

Since it take twice the amount of energy to peel
a unit area of solid-water apart compared to
solid-air, or air-solid, it would seem that the
system would seek to minimize its energy by
spreading the water over the entire surface
(theta-0). However, these values give theta=180,
where the water is only touching at a single
point. This seems a much higher energy state.

What is wrong with my reasoning. Thank you
for any help on this.

--- Bart Killam,  SAS Institute Inc. 
Re: Question on Young's Equation
#54
Author: Umberto D'Ortona
Date: Mon, 12 Oct 1992 09:37
50 lines
2236 bytes
In article <Bvpu7q.1t4@unx.sas.com>, sasrbk@banana.unx.sas.com (Bart Killam) writes:

|> [...]
|>  Young's Equation 
|>    cos(theta)= (sigma_s_a - sigma_s_w)/sigma_a_w
|> 
|> where  
|> 
|>   theta = the connecting angle
|> 
|>   sigma_s_a = interfacial energy between the solid-air
|>               (the energy required to separate a unit
|>                area of air-solid interface)
|> 
|>   sigma_s_w = interfacial energy between the solid-water
|> 
|>   sigma_a_w = interfacial energy between the air-water
|> 
|> Suppose (using J/m**2 or any convenient units)
|> 
|>   sigma_s_a = 1, sigma_s_w = 2 , sigma_a_w = 1
|> 
|> Since it take twice the amount of energy to peel
|> a unit area of solid-water apart compared to
|> solid-air, or air-solid, it would seem that the
|> system would seek to minimize its energy by
|> spreading the water over the entire surface
|> (theta-0). However, these values give theta=180,
No I don't agree with you. If sigma_s_w equal 2,
this mean that the solid-water interface is a high
energy interface (at least higher energy than the
two others) and if the system want to minimize his
energy, it want to have a solid-water interface
as short as possible. So the contact angle will
be 180 degree (0 lenght water-solid interface) 
|> where the water is only touching at a single
|> point. This seems a much higher energy state.
|> 
|> What is wrong with my reasoning. Thank you
|> for any help on this.
|> 
|> --- Bart Killam,  SAS Institute Inc. 

Hope it will help

-- 
Umberto D'Ortona (umberto@aomc.jussieu.fr)
Labo. AOMC   Universite  P.  et  M.  Curie 
4  Pl Jussieu  75252 Paris Cedex 5  FRANCE
Tel: 33 1 44274529      Fax: 33 1 44273854
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