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Started by Bart Killam
Tue, 06 Oct 1992 19:59
Question on Young's Equation
Author: Bart Killam
Date: Tue, 06 Oct 1992 19:59
Date: Tue, 06 Oct 1992 19:59
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2645 bytes
I am having a problem understanding Young's
equation, an equation relating the connecting
angle of an air-water interface (in a air-water-
solid interace) with the interfacial tensions.
The equations seems counter-intuitive, and seems
to violate the principle of least action.
I am reviewing a text (Quantitative Hydrogeology,
de Marsily) that discusses wetting/non-wetting
fluids in a air-water-solid interface. In a
diagram (Fig. 2.12, p 28) of the interface, the
solid boundary is horizonal, with the water forming
a droplet on top. This is probably a common diagram
shown in any soil physics or physical chemistry text.
The angle of the air-water interface is measured
through the water. If the angle < 90 deg. the fluid
is "wetting". This is easy to see; as the angle
approaches 0 deg., the drop spreads out over the
entire surface. Similarly, if the angle > 90 deg.
the fluid is "non-wetting". As the angle approaches
180 deg., the droplet beads up to where only a point
is touching the solid. Again, easy to visualize.
However:
Young's Equation:
cos(theta)= (sigma_s_a - sigma_s_w)/sigma_a_w
where
theta = the connecting angle
sigma_s_a = interfacial energy between the solid-air
(the energy required to separate a unit
area of air-solid interface)
sigma_s_w = interfacial energy between the solid-water
sigma_a_w = interfacial energy between the air-water
Suppose (using J/m**2 or any convenient units)
sigma_s_a = 1, sigma_s_w = 2 , sigma_a_w = 1
Since it take twice the amount of energy to peel
a unit area of solid-water apart compared to
solid-air, or air-solid, it would seem that the
system would seek to minimize its energy by
spreading the water over the entire surface
(theta-0). However, these values give theta=180,
where the water is only touching at a single
point. This seems a much higher energy state.
What is wrong with my reasoning. Thank you
for any help on this.
--- Bart Killam, SAS Institute Inc.
Re: Question on Young's Equation
Author: Umberto D'Ortona
Date: Mon, 12 Oct 1992 09:37
Date: Mon, 12 Oct 1992 09:37
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In article <Bvpu7q.1t4@unx.sas.com>, sasrbk@banana.unx.sas.com (Bart Killam) writes: |> [...] |> Young's Equation |> cos(theta)= (sigma_s_a - sigma_s_w)/sigma_a_w |> |> where |> |> theta = the connecting angle |> |> sigma_s_a = interfacial energy between the solid-air |> (the energy required to separate a unit |> area of air-solid interface) |> |> sigma_s_w = interfacial energy between the solid-water |> |> sigma_a_w = interfacial energy between the air-water |> |> Suppose (using J/m**2 or any convenient units) |> |> sigma_s_a = 1, sigma_s_w = 2 , sigma_a_w = 1 |> |> Since it take twice the amount of energy to peel |> a unit area of solid-water apart compared to |> solid-air, or air-solid, it would seem that the |> system would seek to minimize its energy by |> spreading the water over the entire surface |> (theta-0). However, these values give theta=180, No I don't agree with you. If sigma_s_w equal 2, this mean that the solid-water interface is a high energy interface (at least higher energy than the two others) and if the system want to minimize his energy, it want to have a solid-water interface as short as possible. So the contact angle will be 180 degree (0 lenght water-solid interface) |> where the water is only touching at a single |> point. This seems a much higher energy state. |> |> What is wrong with my reasoning. Thank you |> for any help on this. |> |> --- Bart Killam, SAS Institute Inc. Hope it will help -- Umberto D'Ortona (umberto@aomc.jussieu.fr) Labo. AOMC Universite P. et M. Curie 4 Pl Jussieu 75252 Paris Cedex 5 FRANCE Tel: 33 1 44274529 Fax: 33 1 44273854
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