🚀 go-pugleaf

In <ALIEN.92Aug6090438@vulcan.essex.ac.uk> alien@essex.ac.uk ("Adrian F Clark") writes:


>In article <1992Aug6.111336.9896@waikato.ac.nz> singlis@waikato.ac.nz writes:

>> How do you calculate the FFT of a 2-D image? I assume you calculate the FFT
>> of the row/col of the element (pixel) you are working with.

>The equation that describes the 2-D FFT is `separable', which means
[stuff deleted]
>since this is what happens in real life (i.e., optics).  But don't
>just discard the phase: the information it contains is at least as
>important as that in the modulus!

Ok. Understood. But exactly what does it contain? I just can't seem to
grasp what the phase information in a 2d FFT actually means. I'm after
an intuitive answer, not a mathematical one. With 1d signals, it's a
little bit easier.

>--
> Dr Adrian F. Clark                                   JANET: alien@uk.ac.essex
> INTERNET: alien%uk.ac.essex@nsfnet-relay.ac.uk          FAX: (+44) 206-872900
> BITNET: alien%uk.ac.essex@ac.uk              PHONE: (+44) 206-872432 (direct)
> Dept ESE, University of Essex, Wivenhoe Park, Colchester, Essex, C04 3SQ, UK.

Shckwish!
(Chris Karadaglis, Iconix)