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Article #298

Re: Impredicativity - was: Russell's Paradox

#298
From: Vaughan R. Pratt
Date: Thu, 05 Nov 1992 17:45
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In article <1992Nov5.164251.29649@guinness.idbsu.edu> holmes@garnet.idbsu.edu (Randall Holmes) writes:
>You do not "weaken" FA to AFA; ZFC- + FA and ZFC- + AFA are both
>stronger than ZFC-, but neither is stronger than the other.

I guess this must be another of my misconceptions.  My general
impresssion was that AFA was automatically true under FA, by virtue of
the latter saying that only "unwound" graphs were permitted, and that
every chain on the unwinding had to terminate.  So what's an example FA
situation contradicting AFA?
-- 
Vaughan Pratt				There's no truth in logic, son.
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References: <Bx693z.H37@cantua.canterbury.ac.nz> <1992Nov4.073717.22625@CSD-NewsHost.Stanford.EDU> <1992Nov5.164251.29649@guinness.idbsu.edu>

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From: pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt)
Subject: Re: Impredicativity - was: Russell's Paradox
Message-ID: <1992Nov5.174527.22908@CSD-NewsHost.Stanford.EDU>
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Organization: Computer Science Department,  Stanford University.
References: <Bx693z.H37@cantua.canterbury.ac.nz> <1992Nov4.073717.22625@CSD-NewsHost.Stanford.EDU> <1992Nov5.164251.29649@guinness.idbsu.edu>
Date: Thu, 5 Nov 1992 17:45:27 GMT
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