Re: Polynomials

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#1185

From: Brian Smith
Date: Wed, 04 Aug 2004 12:46

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Jon <jon8338@peoplepc.com> wrote in message news:<J2EPc.23857$iK.8050@newsread2.news.atl.earthlink.net>...
> Polynomial Roots to any Degree
> Vector Calculus Method
> 
> The projection of the curve T onto the normal N results in a logarithmic 
> solution. However, the Taylor coefficients for the logarithmic 
> contribution out-differentiate the polynomial, so it is subtracted as 
> error from the final solution.
> 

Jon, there is a circular argument in your method.

When you construct the equation '-a_0 = Integ (N*dT) dt', the equation
reduces back to the original polynomial.  That circular argument means
that your method fails.

Also, I would like your to see your application of your method to the
equation x^3 - ax^2 + X - a = 0, with 'a' as a variable.  If you
cannot extract 'a' as a root, then your method is useless to get any
exact values.

> 
> http://207.69.235.90/members/jon8338/polynomial/id7.html
> 
> Jon Giffen

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Subject: Re: Polynomials
Date: 4 Aug 2004 05:46:47 -0700
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