Re: Solutions to Power Series

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#1203

From: Proginoskes
Date: Mon, 26 Jul 2004 04:15

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RMoebs1@compuserve.de (Peter Pan) wrote in message news:<3cc72195.0407251355.26ad613d@posting.google.com>...
> Jon wrote 
> 
> > > If T*N+a[0] is the nth degree polynomial where T=(t,t^2,t^3,...,t^n), 
> > > N=(a[1],a[2],a[3],...,a[n]), if T is described from two orthogonal 
> > > systems, its linear requirement precipitates.  T remains invariant
> > > despite the coordinate system used to describe it. Consequently, my 
> > > revised web site showing the details,
>  
> > > EXAMPLE
> > > 
> > > (t-2)(t-3)(t-4)=0
> > > (t^2-5t+6)(t-4)=0
> > >       t-4
> > > -------------
> > > t^3-5t^2+ 6t
> > >    -4t^2+20t-24
> > > ----------------
> > > t^3-9t^2+26t-24
> > > 
> > > N=+/-(26,-9,1)
> 
> REVOLUTIONARY !!!
> 
> Why don't you tell C.F. Gauss or E. Galois; they would love to hear
> that you have easily solved a problem they have shown to be
> principally not solvable!!!

Jon is evidently still using the same wrong procedure. He doesn't come up
with 2, 3, or 4 as roots of the (cubic!) polynomial he gives. (He cheated
by rounding.)
     -- Christopher Heckman

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From: proginoskes@email.msn.com (Proginoskes)
Newsgroups: sci.math.num-analysis,sci.math,japan.sci.math,han.sci.math,fr.sci.maths,aus.mathematics,alt.math.recreational,bln.sci.mathematik
Subject: Re: Solutions to Power Series
Date: 25 Jul 2004 21:15:34 -0700
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