Re: Discrete hyperbolic problem

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#1239

From: Alan Jones
Date: Thu, 03 Jun 1999 00:00

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asj@maths.uq.edu.au (Alan Jones) writes:

>Firstly, the problem cannot be solved unless z is some power of 4 times
>an odd integer.

Mea Culpa. z is either odd or a multiple of four.
(non unique) solutions are (z/4 + 1) and (z/4 -1) in the latter case.

> z odd - a solution of which is
>x = (z+1)/2 and y = (z-1)/2.
>>--
 Alan Jones

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From: asj@maths.uq.edu.au (Alan Jones)
Subject: Re: Discrete hyperbolic problem
Date: 1999/06/03
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