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3 messages
3 total messages Started by Roger Young Wed, 27 Jan 1993 08:34
FEM with SYMMETRIC but NON-POSITIVE stiffness
#1092
Author: Roger Young
Date: Wed, 27 Jan 1993 08:34
47 lines
2188 bytes
I have been following the correspondence in the num-analysis
newsgroup concerning FE methods as applied to symmetric but
non-positive definite matrices.

I appear to have a similar problem with the poro-elastic 
equations. These equations are: (1) the elastic equilibrium
equations with the pressure gradient as a source term (or,
in fact, it can be convenient to work with the variation
of these equations)

	grad(j)d(stress)(ij) = grad(i)d(pressure)

(2) the pressure diffusion equation with an additional time
derivative de/dt of the elastic dilatation e = 
grad(i)(displacement)(i)

	S.d(pressure)/dt + de/dt = -grad(i)q(i)

where the storage S can be taken as constant, and q is the
Darcy velocity which is proportional to pressure gradient
q(i) prop grad(i)(pressure).

In the displacement-pressure formulation the field vector
is chosen as z = (displacement, pressure)^T. Then according
to Lewis and Roberts "The Finite Element Method in Porous 
Media Flow" (in Fundamentals of Transport Phenomena in Porous
Media, eds Bear and Corapcioglu), the finite element equations
for the coupled problem can be written in the form

	K(dz/dt) + Hz = f

where K is SYMMETRIC.

If elasticity is decoupled from pressure, then it appears that 
the reduced stiffness matrix is positive definite for displacement
and pressure individually. However, for the coupled problem
numerical analysis appears to show that K has both +ve and -ve
eigenvalues, ie is not positive definite.

My question(s) are: is this really true? How does one set about
proving (or disproving) positive-definiteness? what is the
physical significance of positive-definiteness?

Any help from readers would be appreciated...

Roger Young (roger@maths.grace.cri.nz) 
Re: FEM with SYMMETRIC but NON-POSITIVE stiffness
#1097
Author: W. Donald Rolph
Date: Tue, 26 Jan 1993 21:45
77 lines
4021 bytes
In article <ROGER.93Jan27083432@kea.grace.cri.nz>, roger@maths.grace.cri.nz (Roger Young) writes:
|> 
|> I have been following the correspondence in the num-analysis
|> newsgroup concerning FE methods as applied to symmetric but
|> non-positive definite matrices.
|> 
|> I appear to have a similar problem with the poro-elastic 
|> equations. These equations are: (1) the elastic equilibrium
|> equations with the pressure gradient as a source term (or,
|> in fact, it can be convenient to work with the variation
|> of these equations)
|> 
|> 	grad(j)d(stress)(ij) = grad(i)d(pressure)
|> 
|> (2) the pressure diffusion equation with an additional time
|> derivative de/dt of the elastic dilatation e = 
|> grad(i)(displacement)(i)
|> 
|> 	S.d(pressure)/dt + de/dt = -grad(i)q(i)
|> 
|> where the storage S can be taken as constant, and q is the
|> Darcy velocity which is proportional to pressure gradient
|> q(i) prop grad(i)(pressure).
|> 
|> In the displacement-pressure formulation the field vector
|> is chosen as z = (displacement, pressure)^T. Then according
|> to Lewis and Roberts "The Finite Element Method in Porous 
|> Media Flow" (in Fundamentals of Transport Phenomena in Porous
|> Media, eds Bear and Corapcioglu), the finite element equations
|> for the coupled problem can be written in the form
|> 
|> 	K(dz/dt) + Hz = f
|> 
|> where K is SYMMETRIC.
|> 
|> If elasticity is decoupled from pressure, then it appears that 
|> the reduced stiffness matrix is positive definite for displacement
|> and pressure individually. However, for the coupled problem
|> numerical analysis appears to show that K has both +ve and -ve
|> eigenvalues, ie is not positive definite.
|> 
|> My question(s) are: is this really true? How does one set about
|> proving (or disproving) positive-definiteness? what is the
|> physical significance of positive-definiteness?
|> 
|> Any help from readers would be appreciated...


This at first glance appears to akin to the problem  that crops up with Lagrange
multipliers (which can masquerade as pressures under many conditions).  If this
is true, then solving for the all elasticity terms connected with a given node
before you solve for any pressure terms for a given node you should find typical
factorization algorithms to work (dont try cholesky decomposition however).

Postive definitenes is in my experience as muchg a religious phenomena as
anything else (opps here go the battles).  Consider however that  if I multply
both sides of a positive definite system by -1 I get a negative definite system,
which is still very well behaved.  In  my experience and from  my religious
framework positive definite means that I have a positive energy functional which
can be minimized (negative definiteness means to me that I have a negative enrgy
functional which needs to be maximized!).

Problems seem to occur for the following conditions:
 
     indefinite - zero eigenvalues
     semidefinite - some are postiive, some are negative

which seems to be your case.  In some cases a semidefinite system can  be
organized as a positive definite system followed by a negative definite system.

Hope these philosophical ramblings more or less answered your question.
-- 

Regards.
 
Don Rolph  a722756@pan.mc.ti.com WD3 MS10-13 (508)-699-1263
Re: FEM with SYMMETRIC but NON-POSITIVE stiffness
#1138
Author: Omar Ghattas
Date: Fri, 29 Jan 1993 04:05
26 lines
2193 bytes
>My question(s) are: is this really true? How does one set about
>proving (or disproving) positive-definiteness? what is the
>physical significance of positive-definiteness?

The existence of a definite coefficient matrix is a sign that the 
operator form of the problem can be obtained by an extremum principle
(minimum principle => positive definite, max => neg def). This is
typically possible for self-adjoint, (positive) definite operators. 
In this case, the Ritz method and the Galerkin method are equivalent, 
and it can be shown that the resulting approximation is optimal, in the 
sense that it minimizes the discretization error (in an "energy" norm). 
It is easy to show that the coefficient matrix must be (positive) 
definite. The classic example is linear elasticity; the minimum 
principle is minimum potential energy or minimum complimentary energy. 
For example, the differential equation for axial deformation of an 
elastic bar -ku" = f can be obtained by finding u(x) that minimizes 
the functional \int 0.5k(u')^2 - fu dx. On the other hand, the 
convection-diffusion equation -ku" + cu' = f is not derivable by 
extremizing a functional, so we cannot expect the coefficient matrix 
be definite. 

Numerically, many nice properties accrue from positive definiteness. 
With direct methods, we need not worry about stability and are free to 
pivot to reduce fill-in. Certain iterative methods (e.g. Jacobi, Gauss 
Seidel, conjugate gradients) are guaranteed to converge from any 
starting iterate. 
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