All Roots to any Polynomial

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3 total messages Started by Jon Mon, 02 Aug 2004 13:46

#1210

Author: Jon
Date: Mon, 02 Aug 2004 13:46

6 lines
1758 bytes

In this development all roots to any degree polynomial are found to any 
desired degree of precision.

http://www.geocities.com/jongiff2000/a7_polynomial_roots_bingo.html

Jon Giffen

Re: All Roots to any Polynomial

#1211

Author: Peter Pan
Date: Mon, 02 Aug 2004 19:17

14 lines
1746 bytes

Jon <jon8338@peoplepc.com> wrote in message news:<410E45F8.3090004@peoplepc.com>...
> In this development all roots to any degree polynomial are found to any 
> desired degree of precision.
> 
> http://www.geocities.com/jongiff2000/a7_polynomial_roots_bingo.html
> 
> Jon Giffen

WARNING !!! WARNING !!! WARNING !!! WARNING !!!

Folks, this is plain nonsense. He can't even find roots for a simple
polynomial of fifth degree: t^5 + t^2 + 1 = 0.

So don't read his bullshit !!!

Re: All Roots to any Polynomial

#1214

Author: Proginoskes
Date: Tue, 03 Aug 2004 07:23

23 lines
2435 bytes

RMoebs1@compuserve.de (Peter Pan) wrote in message news:<3cc72195.0408021117.1c65bf67@posting.google.com>...
> Jon <jon8338@peoplepc.com> wrote in message news:<410E45F8.3090004@peoplepc.com>...
> > In this development all roots to any degree polynomial are found to any 
> > desired degree of precision.
> > 
> > http://www.geocities.com/jongiff2000/a7_polynomial_roots_bingo.html
> > 
> > Jon Giffen
> 
> WARNING !!! WARNING !!! WARNING !!! WARNING !!!
> 
> Folks, this is plain nonsense. He can't even find roots for a simple
> polynomial of fifth degree: t^5 + t^2 + 1 = 0.

Forget polynomials of the fifth degree, his method couldn't even find roots
of a cubic which factors. (He gave one as HIS OWN EXAMPLE of his method
at work. I would have thought he'd post a polynomial where his method
worked.)
     Checking the link, I see he's changed a few things. He doesn't explain
why you can't choose s = 1 and s = 2 as well. (Probably just because they 
don't give valid answers, I bet. And he's doing his old "rounding off"
trick again, claiming it gives exact answers.)
     -- Christopher Heckman

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