Thread View: sci.math.num-analysis
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Started by Paul Bruckman
Mon, 15 Jun 1998 00:00
math help please
Author: Paul Bruckman
Date: Mon, 15 Jun 1998 00:00
Date: Mon, 15 Jun 1998 00:00
12 lines
1562 bytes
1562 bytes
consider the Malfatti circles inscribed in a given triangle ABC. Let A'B'C' be the triangle formed by their centers (corresponding to the vertices A,B,C in the obvious way). Suppose Angles A <=B<=C and A<C. Prove that Angles C'-A' < C-A . Can anybody see a quick solution? It seems to me that the conclusion is that if the Malfatti circles of triangle A'B'C' are also drawn and the process repeated indefinitely, the result (if true) would imply that the limiting triangle would be a point (the incenter I of triangle ABC), but also that the limiting triangle would approach an equilateral triangle. Sincerely, Paul Bruckman
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