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Article #137Number Theory
From: Stan Cabay
Date: Mon, 05 Oct 1992 17:59
Date: Mon, 05 Oct 1992 17:59
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6772 bytes
A student here has some results in number theory which we are
having difficulty in evaluating. I would like any comments
on the results discussed in the following abstract with regards
to new, worthwhile, etc. What are appropriate references?
Stan Cabay
Associate Professor
/* Abstract */
- Functional form invariance plays a key role in number theory.
Composition laws of the Binary Quadratic forms expresses this with
simplest important example coming from Diophantus sum of
squares. The continued fraction expansion for N gives the
well known algorithm for irrational integers.
The solution of Fermat's equation,
(-1)^n = P(n)^2 - N*Q(n)^2,
follows from this algorithm. From a generalization of Diophantus equation
(due to Euler) in the form of a sum of 4-squares and of a sum of 8-squares
(by Caley), we prove the existence of infinite solutions for the
4-D case :
[1] (-1)^n = X(n)^2 + Y(n)^2 - N*( W(n)^2 +Z(n)^2)
and the 8-D case :
[2] (-1)^n = (R(n)^2 + T(n)^2 + X(n)^2 + Y(n)^2) -
N*(U(n)^2 + V(n)^2 + W(n)^2 + Z(n)^2)
for any odd prime N. Generalizing further on the number of variables and
using an application of Hurtwiz-Radon theorem, we prove that all odd
square-free integers > 1 admit a solution to a generalized Fermat equation
(-1)^n = |P(n)|^2 - N*|Q(n)|^2, |a| = modulus of a,
where P(n), Q(n) are VECTOR convergents of order n,
with dimension D=u*2^(4a+b) where a>0, 0<=b<=3, u >1 natural numbers
(this theorem is basically Radon's; Hurtwiz gave the D=2,4,8 cases
to be found on
Hurtwiz - "Uber die Komposition der quadratischen Formen",
Math. Werke, Bd. II, 565-571.
Radon - "Lineare Scharen orthogonaler Matrizen", Math. Werke. )
The existence of the general solution, was found to be numerically
independent of the parity of n (n odd or even), i.e. the negative
unit solution did not discriminate on the representation of N as
sum of K= D/2 +1 (D>2) NON VANISHING squares. The case D=2 is very peculiar
since the number of representations for K=2 sum of squares is exactely 1
when N is 1 mod 4, and only then the solution for n-odd exists.
For D=4*p, p>0, the Hurtwiz theorem gives the conditions for which
the equation below
(x1^2 + X2^2 + ... XD^2) = (y1^2 + y2^2 + ... yD^2)*(z1^2 + z2^2 + ... zD^2)
can hold in the integer field. This equation is clearly a generalized
form of the Diophantus equation for a sum of 2-squares.
When D=4, the algorithm shows that N can in general be written as
the modulus of a complex continued fraction
| A0+iB0 + 1 | 2
| --------------- |
| A1-iB1 + 1 |
N = | ------- |
| A2+iB2 + 1 |
| --------- |
| A3-iB3 + .... |
In short hand notation S(n) = (A(n) +iB(n)) + 1
------ ~=conjugate number
~S(n+1)
is the continued fraction, and its square modulus gives N; in the case D=8 one
would utilize quaternions and take the square norm of a 4-vector.
At the moment, the early results seem to indicate continued fractions
with substantial differences compared with the 2-D case.
The major problem i've encountered lies at the heart of this representa-
tion as sum of K squares. When we have 2-dimensions the problem is indeed well
defined: the representation as sum of 2 squares (for a prime) is unique,
this does not happen in higher dimensions (any prime = sum of three squares
has a very large representations as the size grows!). This latter
fact seems to influence the solutions of [1] and [2] very deeply.
For example : take N = 431 -> 3 mod 4 and -1 mod 8
this number has NO representation as sum of 2 and 3-squares, yet
equation [1] has the solution
-1 = 69^2 +29^2 - 431*(3^2 +2^2)
and all its odd powers (like it's done in the 2-Dim case).
(the corresponding 2-Dim solution does not exist e.g. is not 1 mod 4)
An approximate expansion for N is
| 4-6i + 1 |2
| ------ |
431 = | 1+i + 1 |
| ---- |
| 4 -2i +.... |
My results do not seem to explain why [1] is satisfied for n-odd and N does
not have representations as sum of K=3 squares, nor have I
a well formed explanation for this. The 8-D case follows the same
behavioural path. The periodicity of the fraction seems also to be happening poorly,
I've got some expansions that do not show periodicity at all
(i.e., terminated expansion because A(n)=B(n) = 0) and some that do. I suspect
that this is tied with these multiple representations and to the value K
which is always odd for D >2 (even). In other words, for a sum of K-(odd)
squares the corresponding D-dimensional Fermat equation always has the
negative unit solution (means that -1 is on the LHS of the equation),
a fact that I find very surprising.
To make K-even is to make D=2*(odd number) and such possibility leads us
to say immediately this still gives the same result as the K= odd cases
because for example, in the case D=6, the product of a sum of 6-squares
can be only written as sum of 8-squares which brings us back to K+1=5,
this in turn implies those solution characteristics. Does this then mean that
the negative solution exists for ALL K's >2 ? (i.e. K basically doesn't
matter!). Well, for D>6 The answer (it feels that way) seems to be yes.
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Newsgroups: sci.math.research Path: arc1-ca.pugleaf.net!sparky!uunet!think.com!sdd.hp.com!ux1.cso.uiuc.edu!news.cso.uiuc.edu!dan From: cabay@cs.ualberta.ca (Stan Cabay) Subject: Number Theory Nntp-Posting-Host: stonyplain.cs.ualberta.ca Message-ID: <cabay.718307977@stonyplain> Originator: dan@symcom.math.uiuc.edu Sender: Daniel Grayson <dan@math.uiuc.edu> X-Submissions-To: sci-math-research@uiuc.edu Organization: University of Alberta, Edmonton, Canada X-Administrivia-To: sci-math-research-request@uiuc.edu Approved: Daniel Grayson <dan@math.uiuc.edu> Date: Mon, 5 Oct 1992 17:59:37 GMT Lines: 127