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Article #190A problem of Erdos
From: Steve Finch
Date: Mon, 25 Jan 1993 22:00
Date: Mon, 25 Jan 1993 22:00
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1275 bytes
What is the status of the following problem due to Erdos? Thank you. Please respond via e-mail. Denote by f(n) the largest integer so that, for every sequence of real numbers a(1), a(2), ... , a(n) with a(k) nonzero for all k, one can always select f(n) of them a(j(1)), a(j(2)), ... , a(j(f(n))) with the property that a(j(p)) + a(j(q)) != a(j(r)) for all 1 <= p < q < r <= f(n). PROVE THAT: f(n) = [ (n + 2)/2 ] NOTE: != means "not equal to" and [x] means "greatest integer <= x". REFERENCE: P. Erdos, "Extremal Problems in Number Theory", Proc. Symposia in Pure Math., Theory of Numbers, vol. 8, AMS, pp. 181 - 189.
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arc1-ca.pugleaf.net!sparky!uunet!pmafire!news.dell.com!swrinde!sdd.hp.com!ux1.cso.uiuc.edu!news.cso.uiuc.edu!danShow Full Headers
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Newsgroups: sci.math.research Path: arc1-ca.pugleaf.net!sparky!uunet!pmafire!news.dell.com!swrinde!sdd.hp.com!ux1.cso.uiuc.edu!news.cso.uiuc.edu!dan From: stevef@juliet.ll.mit.edu ( Steve Finch ) Subject: A problem of Erdos Message-ID: <STEVEF.93Jan25170058@oswald.juliet.ll.mit.edu> Originator: dan@symcom.math.uiuc.edu Sender: Daniel Grayson <dan@math.uiuc.edu> X-Submissions-To: sci-math-research@uiuc.edu Organization: M.I.T. Lincoln Lab - Group 43 X-Administrivia-To: sci-math-research-request@uiuc.edu Approved: Daniel Grayson <dan@math.uiuc.edu> Date: Mon, 25 Jan 1993 22:00:58 GMT Lines: 33