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Started by Daniel A. Asimov
Tue, 01 Sep 1992 18:55
Triangulating a Region of R^3 Bounded by Triangulated Surfaces
Author: Daniel A. Asimov
Date: Tue, 01 Sep 1992 18:55
Date: Tue, 01 Sep 1992 18:55
35 lines
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1906 bytes
Some usual definitions (just to avoid any ambiguity): Let k+1 points in R^n be said to be in "general position" if they lie on no (k-1)-dimensional plane. Let a subset S of R^n be called a "k-simplex" if it is the convex hull of k+1 points in R^n in general position. The k+1 points are the "vertices" of S. A "face" of S is defined as the convex hull of a subset of the vertices. Define a compact subset X of R^n to be "triangulated" if X is expressed as the union of finitely many simplices whose pairwise intersection is a common face, or empty. Now: Let M be the closure of a bounded open subset of 3-space, and assume that the boundary of M consists of a finite number of connected components N(i). Assume that each of these N(i) is a compact triangulated surface (without boundary). Call this the "boundary triangulation." QUESTION: Is it necessarily true that M can be triangulated in such a way that the restriction of this triangulation to the boundary of M is the given boundary triangulation? It is easy to see that this is true if M is convex, but what if it isn't? --Dan Asimov asimov@nas.nasa.gov Mail Stop T045-1 NASA Ames Research Center Moffett Field, CA 94035-1000 (415) 604-4799
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