Re: two pairs

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Article #341

#341

From: Robert Strawderman
Date: Tue, 15 Sep 1992 12:19

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You can think of the problem as follows:

You have 13 sets of 4 identical cards, and you first choose two of those sets.  Then,
to get the two pair, you must choose 2 from the 4 in each set.  The remaining card
may be chosen from the 11 remaining sets of 4 cards.  Thus, the numerator is

13C2 * (4C2)^2 * (11 * 4C1)

and the denominator is 52C5.

Rob Strawderman
Dept. of Biostatistics
University of Michigan

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From: rob@med.umich.edu (Robert Strawderman)
Subject: Re: two pairs
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Date: Tue, 15 Sep 92 08:19:43 EDT
Organization: University of Michigan Health Sciences, Ann Arbor
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