Article View: sci.math.stat
Article #476Help with a problem...
From: ytakahashi
Date: Sun, 11 Oct 1992 21:27
Date: Sun, 11 Oct 1992 21:27
29 lines
1299 bytes
1299 bytes
Perhaps someone can help me out... Three people work to solve a problem independantly with differing chances of solving it. Given these probabilities, what is the probability that the problem is solved? Since they are independent, P(AB) = P(A)*P(B) by definition I extended this to... P(ABC) = P(A)*P(B)*P(C) (I'm not sure if that's legal to do) P(AUBUC) = P(A)+P(B)+P(C) - P(ABC) by definition plug in from above yields... P(AUBUC) = P(A)+P(B)+P(C) - P(A)*P(B)*P(C) Is P(AUBUC) actually what I am looking for? Did I do anything illegal (mathematically speaking) here? If this is right, then the probability of the problem being solved is nothing more than the addition of the three individual probabilities minus their product. Right? Any help is greatly appreciated. - Yuki please followup to this as my mail server has been unreliable.
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Path: arc1-ca.pugleaf.net!sparky!uunet!zaphod.mps.ohio-state.edu!darwin.sura.net!jvnc.net!yale.edu!yale!news.wesleyan.edu!eagle.wesleyan.edu!ytakahashi Newsgroups: sci.math.stat Subject: Help with a problem... Message-ID: <1992Oct11.172756.1@eagle.wesleyan.edu> From: ytakahashi@eagle.wesleyan.edu Date: 11 Oct 92 17:27:56 EDT Organization: Wesleyan University Nntp-Posting-Host: eagle.wesleyan.edu Lines: 30