Thread View: sci.math.stat
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Started by Priyabroto
Wed, 16 Dec 1992 01:30
A Simple Question about Instrumental Variables
Author: Priyabroto
Date: Wed, 16 Dec 1992 01:30
Date: Wed, 16 Dec 1992 01:30
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Hi, I had a small question: Let Y = Xb + u (in matrix notation) such that Cov(X,u) is not equal to zero. Now, we use Z as an instrumental variable where: Cov(X,Z) is not equal to zero but, Cov(Z,u) is equal to zero. Then, WHY is it that b hat(instr. var) = (Z'X)inverse * Z'y? As we know b hat = (X'X)inverse * X'y. Would really appreciate any help.
Re: A Simple Question about Instrumental Variables
Author: T. Scott Thompson
Date: Wed, 16 Dec 1992 17:22
Date: Wed, 16 Dec 1992 17:22
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bubai@matt.ksu.ksu.edu (Priyabroto) writes: >Hi, >I had a small question: >Let Y = Xb + u (in matrix notation) >such that Cov(X,u) is not equal to zero. >Now, we use Z as an instrumental variable where: >Cov(X,Z) is not equal to zero but, >Cov(Z,u) is equal to zero. >Then, WHY is it that b hat(instr. var) = (Z'X)inverse * Z'y? I don't understand the question. This is the _definition_ of the IV estimator (assuming that Z and X have the same dimensions). The statistical motivation for the estimator comes from the fact that Inverse(Z'X)*Z'y = b + Inverse(Z'X/n)*(Z'u/n) and the last term converges to zero in large samples due to the law of large numbers and the assumption that E(Z'u) = 0. >As we know b hat = (X'X)inverse * X'y. This is the definition of the least squares estimator, which is not the same as the IV estimator, and which does not converge to b in large samples when X and u are correlated. Perhaps you are asking how to show that the IV estimator and the least squares estimator are the same thing. This cannot be done in general. The least squares estimator can be thought of as a special case of the IV estimator obtained by setting Z = X. -- T. Scott Thompson email: thompson@atlas.socsci.umn.edu Department of Economics phone: (612) 625-0119 University of Minnesota fax: (612) 624-0209
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