🚀 go-pugleaf

I'd just like to add a little elaboration on the topic of driven resonance
to Terry Bollinger's discussion of cavitation.

If you set up system of standing waves as Terry suggests, you will have
created a driven resonance system.

In such systems (as Tesla was fond of dramatically demonstrating) energy is
accumulated over many cycles, making the amplitude of each cycle successively
larger until a limit is reached.

For instance, in the case of a cyclical system in which the energy loss rate
is proportional to the amplitude, and say, for instance, accounts for 10%,
then the amplitude after several cycles will be the inverse of the loss rate,
(or 10 times in this case) of the amplitude of the first cycle (or of a
comparable single shot device.) 

This ratio of first cycle amplitude to later maxed out amplitudes is known as
the "Q" of the resonance (though there is a more precise definition of "Q".)

Another way to look at it is to see that the amplitude of the oscillation
and its proportional fraction of energy loss (to heating, etc) will continue
to grow until the amount of energy loss grows to just equals the amount of
driven energy being input on each cycle.  The oscillation amplitude stops
increasing when all the input energy is being consumed to cover the energy
loss mechanisms.

Therefore if you have a very efficient oscillator (low fraction of energy
loss per cycle) then you can have very high "multiplications" of the
"driver" amplitude.

A loss rate of 10% would mean an amplification of 10.
A loss rate of 1% would mean an amplification of 100.
A loss rate of 0.1% would mean an amplification of 1000.

-- 
- John Logajan MS010, Network Systems; 7600 Boone Ave; Brooklyn Park, MN 55428
- logajan@network.com, 612-424-4888, Fax 612-424-2853