🚀 go-pugleaf

$$                 Emit detect Dirac ambient h*fL.
$$  Note EMiTTER side 4*(pi)^2*Rx typo-CORRECTiON @ item 2 ..below.

    > Length is not an intrinsic physical property of the spaceship,
    > so asking whether it "PHYSICALLY increases or decreases" -=-

[ESPECiALLY in GR, WHERE the GR TEST-mass is a GR POiNT-mass ONLY.!!]

PUT GR aside:..
 1. h/2*pi*c = me*wls = {mph}*ls = Moo*loo/4*pi = eR*loo/2*pi*c^2.

 2. h*fL = pL*c = nL*h*c / wl = m1*c^2 = nA*{mph}*ls*c^2 / rA, ENERGY;
      = pi*(h + nA*hbar) / (pi + 1)*sec ..The ENERGY for at a RECiEVER;
     = 2*pi*(h + 2*hbar) / (2*pi + nA)*sec ..The ENERGY for an EMiTTER;
            = (m1*v1^2/2)*{(m1/M1) + 1), The GUESS STANDARD LaGrangian.
SAME...
Reciever DETECTOR (on LEFT side) || Planck EMiTTER energy h*fL (below);
                                 ||
  pi*(h + nA*hbar)               ||  2*pi*(h + 2*hbar)
= -- -- ---  -- -- = -- -- --- --||= -- -- -- -- -- --; = -- --- -- --
    (pi + 1)*sec                 ||   (2*pi + nA)*sec
                                 ||
 2*pi*(h + nA*hbar)              ||        Ra*h         2*pi*Ra*hbar
= -- -- -- -- -- -- = -- -- -- --||= -- -- --- -- -- = -- -- --- -- --
       Ra*sec                    ||  (2*pi + nA)*sec   (2*pi + nA)*sec
                                 ||
  2*pi*(h + nA*hbar)*Ni          ||  (PLANCK Temp Tp)*h
= -- -- -- --- -- -- -- = --- ---||= -- -- --- -- -- -- = -- --- -- --
  (PLANCK Temp Tp)*sec           ||  (2*pi + nA)*Ni*sec
                                 ||
  (h + nA*hbar)*hbar             ||    4*(pi)^2*Rx  <- Typo-CORRECTED;
= -- -- --- -- -- -- = -- - -- --||= -- -- --- -- -- = -- -- --- -- --
        Rx*sec                   ||  (2*pi + nA)*sec
                                 ||
LEFT side is a RECiEVER, DETECTOR|| The RiGHT side is an h*fL EMiTTER. 

SAME, but for the AMBiENT media, or, *iN-TRANSiT-space* ENERGY, h*fL;

  |nA*{mph}*ls*c^2|   nL*h*c   | m1*v1^2   m1     |          |      |
= |-- -- --- -- --| = --- -- = |(-- - --)*(-- + 1)| = pL*c = |m1*c^2|.
  |      rA       |     wl     |    2      M1     |          |      |
$$                           STANDARD LaGrangian form.

Sun RADiATEs @ AMBiENT; AMBiENT RADiATEs 1400 Watts/m^2 @ 1*AU radius.

3. RESTmass*c^2 = iNTRiNSiC REST energy eM = EQUiVALENT energy e.










Old GR EQUATiON had no LaGrangian L ..and no ANGULAR momentum pA.
$$                   GR equation corrected:
 GUESS iSS GR G_uv = G_absolute/G = 1/(n - 1) = G_relative = Gr. 

$$   ENTHALPY E = m*c^2 + LaGrangian L + Volt*Amp*sec energy eV;
                = eM    +     L        +     eV
                = m*c^2 +    pL*c      +    pA*fA
                = m*c^2 +    pL*c      - (me*v^2 / 2)
                = m*c^2 +   m1*c^2     - (me*v^2 / 2)
                = m*c^2 +    h*fL      +    pA*fA
                = m*c^2 +    h*fL      +  nA*hbar*fA
                = m*c^2 + nL*h*c / wl  +  nA*hbar*fA
     = iNTRiNSiC energy + LaGrangian L + Volt*CHARGE energy eV
     = eM + L + eV   ..THiS LiNE and NEXT are *MUTUALLY-exclusive*;
     = eM + L - (me*v^2 / 2) ..a NET energy caN'T be BOTH, at once;
     = eM + eK
     = eF + L + eK
     = eG + eK - eV   ..THiS LiNE and NEXT are *MUTUALLY-exclusive*;
     = eG + eK + (me*v^2 / 2) ..a NET energy caN'T be BOTH, at once.

$$  Hamiltonian ANALYSiS confused POTENTiAL energy especially, which
    is WHY it only fits with LaGrangian ANALYSiS in PARTiCULAR cases.
    You CAN only understand this if REST mass*c^2 = iNTRiNSiC energy.
    Note c constant is NOT equal to 1 in GUESS iSS units, but arrives
    at the SAME ANSWER ..and also, with the SAME FORM as GiVEN above.

RePOST:              iNTRiNSiC energy (jiM Carr).
Re: Do Photons Have Mass?; Date: Mon, 15 Jan 2001 20:05:56 GMT
--------------------------------------------------------------
srp (srp@microtec.net) wrote: >  >  >  Jim Carr a Ècrit :
In article <3a362709.3795467@news.uq.edu.au> this@will.bounce writes:
>  >  >  >  > Mass is equivalent to energy and photons of course have
>  >  >  >  > energy.
>  >  >  >
>  >  >  >  Only partly true.  Mass is equivalent to (what I call)
>  >  >  >  _intrinsic_ energy, the energy a particle has that is
>  >  >  >  unrelated to its motion.
>  >  >  >  The relation is that m = sqrt{ E^2 - (pc)^2 }/c^2.
`````snip`````
>  >  Note the sign. He's *subtracting* the momentum contribution
>  >  from the total energy. What's left is the intrinsic energy.

[arcsign to srp]; YES, exactly, 'iNTRiNSiC energy' is just ANOTHER
simple SYNONYM for (REST-mass)*c^2=(Rebel-GR-invarint REST-mass)*c^2.

>  -- >   André Michaud
>  Service de Recherche Pédagogique http://www.microtec.net/srp/
>  La nouvelle "Société Royale" http://www.microtec.net/srp/socroyfr.htm
>  "Les choses n'arrivent dans ce monde que lorsque quelqu'un les fait
>  arriver" - Anonyme.
>
>  Sent via Deja.com >  http://www.deja.com ® © ¿ End of rePOST.
[SPEEDo.wpd]; $$ $$    $$ $$    $$ $$    $$ $$  $$  End of POST.
Re: EMiTTER side 4*(pi)^2*Rx typo-CORRECTiON @ item 2 on Page 1.
Re: Emit detect Dirac ambient h*fL.