🚀 go-pugleaf

Bilge wrote: >  >  guskz@hotmail.com:
>  >I find it a VERY interesting and perplexing question because if
>  >HEAT IS NEVER LOST and only shifts to other locations ....
>  >
>  >THEREFORE the very thermodynamic laws affecting the Big Bang
>  >would be "quazy" wrong since the Universe never actually does
>  >"cool" down and the original heat (quantity of heat) of the
>  >explosion will NEVER go away thus interfering with the cooling
>  >down theory???
>                            PV = nkT
$$       Pauli EXCLUSiON factor k, in Big Bang GR (Bilge).
$$ Pressure*Volume = n*k*degKelvin ..k is Boltzmann/Pauli PARTiTiON k.
 'Statistical Physics for Students of Science and Engineering'; Dover.
 E = eM + eK = iNTRiNSiC energy + LaGrangian L + Volt*A*sec energy eV.
 Where, LaGrangian L = degKelvin*entropy[S] ..and, E = Total ENTHALPY.
 Where Pa = Pascal PRESSURE ..and degK = Kelvin Temperature. ```Brian.
 -=-
>   However, your question is completely answered by the first law
> of thermodynamics: dU = dQ - dW, or the change in internal energy is
> equal to the change in heat minus the work done by the system.
 -=-
>  >> Example: >  >> -=-
>  >> water particles turn turbines (converts to kinetic energy) but
>  >> the water itself never disappears (or becomes converted)
>  >> ...therefore is it likewise for Temperature??
>  >>
>  >> If so this should have implications on the laws of thermodynamis
>  >> with regards to the ***BIG BANG*** and the final suggested state
>  >> of the Universe? >  >
Re: Pressure*Volume = n*k*degKelvin ..k is Boltzmann/Pauli PARTiTiON k.
Re: Pauli EXCLUSiON factor k, in Big Bang GR (Bilge).