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Thread View: sci.physics.fusion
3 messages
3 total messages Started by brian a m stuckless Thu, 16 Feb 2006 08:02
AC=Alternating DC, Dimwit.
#1370
Author: brian a m stuckless
Date: Thu, 16 Feb 2006 08:02
43 lines
2854 bytes
$$  Any QUANTiTY of the form m1*v1^2/2 is Volt*CHARGE, V*Amp*sec.
                                                        ```Brian.
PD wrote: > > guskz@hotmail.com wrote: > > PD wrote:
> > > For example, electrons carry charge and electromagnetic
> > > radiation does not; both carry energy and momentum. Thus,
> > > we know that electromagnetic radiation is not carried by
> > > electrons because no *charge* is carried away from the
> > > source, though momentum and energy most certainly are.

$$  Any QUANTiTY of the form m1*v1^2/2 is Volt*CHARGE, V*Amp*sec.
                                                        ```Brian.
> > > PD > >
> > 1. How is it determined that no charge is carried away?
>
> Lots of ways. An ammeter would measure the charge carried away
> as a DC (not AC) current.

$$  AC current is an Alternating DC current, Dimwit. ```Brian.
 
> -=- There is no DC current measured in a radio antenna.
> 
> >
> > 2. An electron traveling in a wire generates an EM wave
> > perpendicular to its direction....does a photon alos generate
> > an EM wave perpendicular to its direction???
>
> No. Remember: light (EM radiation) has both particle and wave
> aspects.

$$ Technically, "light" AND "heat" ARE "..the same thing", idiot.

> EM radiation, photons, they are all labels for *the same thing*.
>
> So when you make a statement like "does a photon also generate an EM
> wave," you're asking whether light generates light. The answer to that
> is no.
>
> > (I think I read it has a magnetic
> > field (EM)perpendicular to its direction....which is strange
> > since the photon itself is an EM wave)
Re: Questions about radiation and em waves
Re: Any QUANTiTY of the form m1*v1^2/2 is Volt*CHARGE, V*Amp*sec.
Re: AC=Alternating DC, Dimwit.
Re: AC=Alternating DC, Dimwit.
#1372
Author: Mitchell Dickson
Date: Thu, 16 Feb 2006 12:05
47 lines
3297 bytes
> > > > For example, electrons carry charge and electromagnetic
> > > > radiation does not; both carry energy and momentum.

Electromagitism "IS" the charge carried by electrons.
Thus,
> > > > we know that electromagnetic radiation is not carried by
> > > > electrons because no *charge* is carried away from the
> > > > source,
Magnets are the source.  All electrical energy is produced by magnets.


> > > 2. An electron traveling in a wire generates an EM wave
> > > perpendicular to its direction....does a photon alos generate
> > > an EM wave perpendicular to its direction???
> >
> > No. Remember: light (EM radiation) has both particle and wave
> > aspects.

Bear in mind that magnets are much, much smaller than photons!!!!!!!  Light
cannot penetrate a 6 mil piece of black plastic for instance or a thin piece
of wood, magnets have no problem at all doing so.
>
> $$ Technically, "light" AND "heat" ARE "..the same thing", idiot.
>
> > EM radiation, photons, they are all labels for *the same thing*.

Bull!
> >
> > So when you make a statement like "does a photon also generate an EM
> > wave," you're asking whether light generates light. The answer to that
> > is no.

LMAO!  Yes but the photon must travel on an electromatic wave.  It may not
generate the wave but it's travel is dependent on a wave being present.  It
is the old chicken or the egg thingy :)

Look,  you know that Faraday proved that if you draw a magnet through a
copper coil a current will be produced.  What they left out of your book is
that you CAN glue the magnet to the coil and if both are moved together in
space (turned for instance) the same current is produced!  Now that wads up
the paper the laws of thermodynamics are written on and we couldn't have
that could we?  Best to leave that part out :)  It might lead one to zero
points and space/time anomolies and such ;)  Electricity is only part of the
riddle of magnets.

Mitch
>
Re: AC=Alternating DC, Dimwit.
#1329
Author: hhc314
Date: Fri, 17 Feb 2006 21:27
43 lines
3081 bytes
Mitch posted this humorous bit of fantasy:

"Look,  you know that Faraday proved that if you draw a magnet through
a
copper coil a current will be produced.  What they left out of your
book is
that you CAN glue the magnet to the coil and if both are moved together
in
space (turned for instance) the same current is produced!"

This is of course total nonsense. If there is no change in the magnetic
flux density within the coil, neither voltage nor a resulting current
is produced.  As Faraday put it:

E = - N dB/dt

Where: E is the voltage indiced; N is the number of turns in the coil,
and dB/dt is the time rate of change in the magnetic flux density
passing through the coil. With the magnet glued to the coil (excluding
variations in the permeability of space), no voltage or current is
produced.

Mitch, since this is such very basic material I have to allow that you
may have posted it as a joke to the ever clueless Brian  Stuckless, and
simply overlooked posting the smiley emoticon indicating the nature of
your followup. Other silly and untrue things that you've posted support
this interpretation, such as:

"All electrical energy is produced by magnets."
(Batteries produce electrical energy without the use of magnets.

"Light cannot penetrate a 6 mil piece of black plastic for instance or
a thin piece
of wood, magnets have no problem at all doing so."
(This completely overlooks the fact that magnetic fields and
electromagnetic waves are completely different things. Also,
electromagnetic waves (photons if you prefer) such as x-rays and radio
waves can penetrate objects that are opaque to light in the visible
spectrum).

Post some more funny stuff, it keeps my kids amused!  :-)

Kindest regards,   Harry C
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