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Hi my name Is Conrad Countess

I have a geometrical interpretation of E=mc^2 in which an EM wave
changes into a backward spinning standing spherical wave that makes 2
rotations to complete one wave cycle and has rest mass. I do believe
that it is no coincidence that these are the same properties
attributed to electrons and that this is indeed a geometrical
description of an electron. First I assumed that analogous to a line
of 1 inch in the horizontal direction times a line of 1 inch in the
vertical direction to equal a square inch, c^2 is the speed of light
in the linear direction times the speed of light in the 90 degree
angular direction that is only reached at the high end of EM spectrum
where frequency is highest. This should create a balance of
centripetal and centrifugal forces to create circular or spherical
motion. Not only is this how orbital and circular motion is viewed
sometimes, it is also measured as (a=v^2/ r) which is acceleration of
circular motion equals velocity squared divided by the radius. If we
substitute c^2 for v^2 as it is said that Einstein did when he derived
E=mc^2 from F=mv^2 we can see how c^2 could refer to the speed of
light in circular motion in this case. Furthermore if one draws an arc
from the beginning of the horizontal line to the top of vertical line
we get a 90 degree arc which if constant will create a circle.
As it turns out, an electrons diameter would be the same measure as
the full amplitude, (positive +negative) of an EM wave such as a gamma
ray, if one looks at the electron as a sphere ,and its radius half
that. But if it is considered a circle folded in half as two circles
at right angles to each other, as indeed an electron is considered a
spin 1/2 particle that makes two rotations in order to complete one
wave cycle, than the diameter of the sphere is the radius of the
circle.
One final thing according to this site
http://www.colorado.edu/physics/2000/quantumzone/debroglie.html

de Boglie assumed that any particle, photon or electron would have a
wavelength equal to h/p or Planck's constant divided by the momentum.
This put Electron along the same wavelength spectrum as EM waves.
Furthermore Bohr set the wavelength of electron equal to circumference
of a circle with an angular momentum of an integer multiple of h/2pi.
This fits in seamlessly with my idea that an electron emerges from and
EM wave spectrum because of a high enough momentum to create circular
motion and rest mass.
This also fits in seamlessly with my idea that the radius or diameter
of electron would be same as full amplitude of an EM wave, and I chose
gamma rays because they are the closest in momentum to electron, and
that c^2 occurs when the speed and momentum of the wave in the 90
degree angular direction equals the speed and momentum of light in the
linear direction, resulting in a balance of centripetal and
centrifugal forces and circular or spherical motion, such as binding
energies and standing spherical waves like electrons. And this happens
because of the 90 degree arc trajectory that the wave takes which if
constant creates a circle.
I also equate, as many do (h = c), and sense the circumference of a
circle, (which can be equated with wavelength of electron according to
Bohr), can be derived from  from formula (Radius x 2pi), the momentum
being inversely proportional to it  indicates that the radius must be
h as in h/2pi or c as I measured it in my geometrical interpretation
as c in linear direction times c in 90 degree angular direction
resulting in a 90 degree arc which if constant creates a circle. The
length of one of the lines of force representing speed of light in
linear or 90 degree angular direction as it creates the 90 degree arc
and before it continues into a full circle, would be the radius of an
electron.

Also see: http://docs.google.com/Doc?id=dsn5q6f_11vv737cck
http://docs.google.com/Doc?id=dsn5q6f_209723wdc9


Conrad Countess