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Article #1066

Re: DARK ENERGY OR TIRED LIGHT (DECREASED SPEED OF PHOTONS)?

#1066
From: glird
Date: Sun, 04 Oct 2009 22:15
32 lines
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On Oct 4, 2:27 am, john <vega...@accesscomm.ca> wrote:
> Our concept of gravity is backward.
> How can every iota of matter possibly
> put out an infinite number of gravitons?
> Matter absorbs some sort of radiation.
> It is the absorption of this common component
> that creates the sinks.
> Electrons are negative charge whipping
> around in *very* small circles.
> That has to radiate.
> Yet we don't detect it.
> What if that radiation is at a much higher
> frequency and speed, while being a
> much smaller version "photon"?
> Why couldn't gravity-causing radiation
> also be off the charts, frequency-wise and
> using much smaller units?

  Because gravity isn't caused by radiation.
   A gravitational FIELD is a density grdient in matter-filled space.
 Because atomic particles are made of this one compressible matter
they will be part of any g-field in which they are embedded. Because
every atom has a spinning nucleus and - for reasons not presented here
- has its own density gradient centered on that nucleus, the overall
grad d of the g-field will sum with that of each component atom.
Since the resistance to further compression is greater on the denser
side(s) a net pressure in the direction of greater density will
therefore arise INSIDE of every component atom.  It is this net-
pressure that is the gravitational FORCE. It does not exist in the g-
field per se; it arises inside of embedded particles.

glird
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From: glird <glird@aol.com>
Newsgroups: sci.physics.relativity,sci.physics,fr.sci.physique,fr.sci.astrophysique
Subject: Re: DARK ENERGY OR TIRED LIGHT (DECREASED SPEED OF PHOTONS)?
Date: Sun, 4 Oct 2009 15:15:47 -0700 (PDT)
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