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Article View: sci.physics.relativity
Article #6009

Re: EXPERIMENTS THAT REFUTE RELATIVITY

#6009
From: Pentcho Valev
Date: Mon, 10 Dec 2007 11:16
102 lines
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On Dec 9, 15:17, Pentcho Valev <pva...@yahoo.com> wrote:
> On Dec 6, 4:37 pm, Tom Roberts <tjroberts...@sbcglobal.net> wrote in
> sci.physics.relativity:
>
> > Pentcho Valev wrote:
> > >http://philsci-archive.pitt.edu/archive/00001743/02/Norton.pdf
> > > John Norton: "Einstein regarded the Michelson-Morley experiment as
> > > evidence for the principle of relativity, whereas later writers almost
> > > universally use it as support for the light postulate of special
> > > relativity......THE MICHELSON-MORLEY EXPERIMENT IS FULLY COMPATIBLE
> > > WITH AN EMISSION THEORY OF LIGHT THAT CONTRADICTS THE LIGHT
> > > POSTULATE."
>
> > Sure. The fact that this one experiment is compatible with other
> > theories does not refute relativity in any way. The full experimental
> > record refutes most if not all emission theories, but not relativity.
>
> > > THE POUND-REBKA EXPERIMENT IS FULLY COMPATIBLE WITH AN EMISSION THEORY
> > > OF LIGHT THAT CONTRADICTS THE LIGHT POSTULATE.
>
> > Sure. But this experiment, too, does not refute relativity. The full
> > experimental record refutes most if not all emission theories, but not
> > relativity.
>
> > > Indeed, the Pound-Rebka experiment confirmed the equation f'=f(1+V/
> > > c^2) which is EQUIVALENT to Einstein's 1911 equation c'=c(1+V/c^2)
> > > which is EQUIVALENT to the equation c'=c+v given by the EMISSION
> > > theory of light.
>
> > This is just a repeat of the nonsense you continually attempt to
> > promulgate. The "equivalence" you claim is wrong, and is based on
> > intermixing various INCOMPLETE ideas and applying them outside their
> > domains of validity....
>
> > Einstein himself abandoned that 1911 equation in favor of GR, in which
> > it is seen that the equation is an APPROXIMATION that applies ONLY to a
> > specific and unusual physical situation.
>
> A simple exercise for you and your zombies Roberts Roberts. You have:
>
> c = f * L     initially
>
> c' = f' * L'    finally
>
> f' = f(1+V/c^2)      confirmed experimentally
>
> c' = ? L' = ?
>
> You have ONLY TWO possible solutions Roberts Roberts:
>
> Solution 1: c' = c ; L' = L/(1+V/c^2)
> This solution has been rejected by Albert Einstein in 1911 and,
> implicitly, by Tom Roberts a century later. Tom Roberts wrote in
> sci.physics.relativity:
>
> > Pentcho Valev wrote:
> > > CAN THE SPEED OF LIGHT EXCEED 300000 km/s IN A GRAVITATIONAL FIELD?
> > Sure, depending on the physical conditions of the measurement. It can
> > also be less than "300000 km/s" (by which I assume you really mean the
> > standard value for c). And this can happen even for an accelerated
> > observer in a region without any significant gravitation (e.g. in
> > Minkowski spacetime).
> > Tom Roberts tjrobe...@lucent.com
>
> Solution 2: c' = c(1+V/c^2) ; L' = L
> This solution has been confirmed by Albert Einstein in 1911 and,
> implicitly, by Tom Roberts a century later.
>
> A somewhat more difficult exercise Roberts Roberts is one where you
> will have to prove that Einstein's 1911 equation c'=c(1+V/c^2) is
> EQUIVALENT to the equation c'=c+v given by the emission theory of
> light. That is an exercise for YOU, not for your zombies.

Roberts Roberts you may not know how to prove the equivalence of
c'=c(1+V/c^2) and c'=c+v so let me guide you through the difficulties.
A light source at the top of a tower of height h emits photons with
speed c (relative to the source). The photons accelerate so that, when
they reach a receiver on the ground, their speed (relative to the
receiver) is

c' = c(1 + gh/c^2)               /1/

which is Einstein's 1911 equation.

Now a rocket with length h accelerates with acceleration g. A light
source at the front end emits photons with speed c (relative to the
source). When the photons reach the receiver at the back end, this
receiver has a speed v relative to the light source at the moment of
emission. What is the speed of the photons, c', relative to the
receiver, at the moment of reception?

You should only apply Einstein's equivalence principle Roberts Roberts
and see that

gh = cv               /2/

Substitute this into /1/ and you obtain

c' = c + v                     /3/

Pentcho Valev
pvalev@yahoo.com
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From: Pentcho Valev <pvalev@yahoo.com>
Newsgroups: sci.physics.relativity, sci.physics, fr.sci.philo, 
 fr.sci.physique, fr.sci.maths
Subject: Re: EXPERIMENTS THAT REFUTE RELATIVITY
Date: Mon, 10 Dec 2007 03:16:14 -0800 (PST)
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