🚀 go-pugleaf

"Gordon Stangler" <gordon.stangler@gmail.com> wrote in message 
news:3b0f30a7-88c3-4376-8338-fe9f2352980c@g15g2000pra.googlegroups.com...
> Pentcho,
>
> In one frame, the pole is length contracted to fit inside the barn,
> and the barn doors are closed simultaneously, trapping the pole
> inside.  The doors are then opened, allowing the pole to pass through.
>
> In the other frame, the barn is length dilated, but the barn doors are
> closed, first one, then the other, and opened one after another,
> <different times>.  We have to drop simultaneity in order to get the
> pole through the barn.
> Hope this helps.


Suppose the length of the barn is 10m, and the length of the
pole is also 10m when at rest in the barn.
Being a barn, it is closed at one end and the door is closed
as the pole enters. It will fit when at rest.

 Calculate the length of the pole when moving at 0.866c.

xi = (x-vt)/sqrt( 1-v^2/c^2)
  http://www.androcles01.pwp.blueyonder.co.uk/Smart/x'=x-vt.gif

xi = (10m)/sqrt (1-0.866^2/1^2)
 = (10m)/sqrt (1-0.75)
 = (10m)/sqrt (0.25)
 = (10m)/0.5
   = 20m
It will not fit until it is brought to a sudden stop.

Your idiot drool doesn't help at all, you are a fuckwit.
Why do you incompetent fuckin' lunatics call it length
 "contraction"?