🚀 go-pugleaf

On Apr 21, 10:17 pm, Tom Roberts <tjroberts...@sbcglobal.net> wrote in
sci.physics.relativity:
> bkh99 wrote:
> > The problems have increased in the last decade as certain
> > experiments have produced results that violate fundamental postulates
> > of Special Relativity ("nothing can travel faster than the speed of
> > light", this speed of light being some kind of magic number).
>
> This is just plain wrong. At present, there is no reproducible
> experiment within its domain that disagrees significantly with SR.

A light source on top of a tower of height h emits light with
frequency f, speed c (relative to the source) and wavelength L. A
receiver on the ground receives light with frequency f', speed
c' (relative to the receiver) and wavelength L'. According to Newton's
emission theory of light:

f'=f(1+gh/c^2); c'=c(1+gh/c^2); L'=L

A rocket of length h accelerates with acceleration g. A light source
at the front end emits light with frequency f, speed c (relative to
the source) and wavelength L. A receiver at the back end receives
light with frequency f', speed c' (relative to the receiver) and
wavelength L'. At the moment of reception, the receiver has speed v
relative to the light source at the moment of emission. According to
Newton's emission theory of light:

f'=f(1+v/c); c'=c+v; L'=L

As you can see, Honest Roberts, Newton's emission theory of light
predicts that, in the accelerated frame, both the frequency and the
speed of light vary and the respective equations are f'=f(1+v/c) and
c'=c+v. You also know, Honest Roberts, that f'=f(1+v/c) has been
EXPERIMENTALLY confirmed by Pound and Rebka.

What does special relativity predict, Honest Roberts? What speed of
light will the receiver (observer) in the rocket measure, according to
special relativity? c'=???, Honest Roberts? If you want to introduce a
red herring, at least introduce it clearly, e.g. in the following way:

"I, Honest Tom Roberts, solemnly declare that special relativity gives
no prediction whatsoever concerning the speed of light an accelerated
observer (or, equivalently, an observer in a gravitational field)
measures because the observer is accelerated and special relativity
does not deal with accelerated systems."

Then, Honest Roberts, brothers Einsteinians will conclude: "Newton's
emission theory of light predicts c'=c+v, where v is the speed of the
light source relative to the observer. Master Tom Roberts says special
relativity gives no prediction. Therefore the emission theory is
refuted (if not by this particular experiment, by other experiments)
whereas special relativity is not refuted and will never be."

Pentcho Valev
pvalev@yahoo.com