🚀 go-pugleaf

Take two observers and a source of photons.  Place all three in deep
space sufficiently shielded so that the effects of the rest of the universe
are unimportant (he says, smilingly..).  Put one observer 3 meters "south"
of the photon source.  Put one observer 4 meters "west" of the source.  
So now we know where everyone is.  Every second, the photon source is made
to give off a photon.  Now either the photon collapses at the first observer,
the second observer, or the rest of the universe (probably the isolation
shielding).  If the photon collapses at the first observer, then the second
observer should be able to determine this fact by observing that he did NOT
observe the photon and the shielding did not observe the photon (detector of
some sort . . . how about a thermometer :-).  Thus the fact that the photon
collapsed at the first observer is NOT discernible before a photon could
travel along the entire surface of the shielding which is SLOWER than a
photon travelling between the two observers.  The information that the second
observer obtains does not travel between observers faster than light, because
the second observer cannot know whether either observer was actually
"there" when the photon collapsed.
Okay, new experiment... Two hemispherical photon-detectors.  Same type of
experiment.  Same result.  Same explanation...
What's the problem?

--Eric Gindrup ! gindrup@hardy.math.okstate.edu