Article View: sci.physics
Article #1179Re: snarfy's reply to McIrvin
From: Mcirvin
Date: Wed, 12 Aug 1992 01:20
Date: Wed, 12 Aug 1992 01:20
198 lines
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11471 bytes
snarfy@cruzio.santa-cruz.ca.us writes: > [...] In > other words ,once something becomes an absorber of electromagnetic > radiation it too becomes an emitter and what was at a previous time the > emitter at that point is now another absorber (from the reference frame > of the first absorber ,object B). This is indeed how such calculations are usually done. The argument put forth here by others is that the steady-state situation corresponds to a continuous series of transmitted waves from A to B and from B to A; and that putting the load at point B changes its characteristics as an emitter, causing a change in the emitted waves from B to propagate back at c. > Any symmetry between an emitter and absorber ,as in resonance ,demands > that both the ``retarded'' and ``advanced'' solutions to Maxwell's > equations be put on equal footing . I'm not so sure about this. If the scenario you've depicted with A and B is in one dimension, so that there can be a standing wave in the box in between, I agree. Such a wave can be modeled just as well with retarded or advanced solutions, as long as the situation has been and remains forever in a steady state with no changes to the object at B. In more dimensions, it might likewise be just as easy to model the system either way if the whole setup is in a large conducting box, or some such thing. If A and B are in empty space, though (and this is being considered as a method of interstellar communication), waves will travel outward from A and likewise outward from B, unless the boundary conditions at large distances in the past have been set up in a very, very special way (see below). Both A and B can be considered both emitters and absorbers, and if they're both supplied with power so that they broadcast at equal strength, there is a symmetry between them; but the system will clearly correspond to a retarded solution. > The retarded solutions usually refer > to the sequence cause -> effect , while the advanced solutions are often > referred to in terms of a backward sequence in time, effect -> cause; > which solutions, if applied, make it appear that the sequence in question > violates the law of causality. Again ,to avoid this apparent conflict in > the context of Maxwell's equations we must reverse the names emitter and > absorber. Actually, it's a matter of boundary conditions. When properly considered, advanced solutions don't violate causality at all; they just make assumptions about past boundary conditions rather than future ones. Emitters do become absorbers in the process, but it's necessary to remember how the situation is set up. Consider an antenna which emits a pulse of radio waves. This pulse travels away to infinity. Electrodynamics is time- symmetric, though, and we can just as easily imagine a wave coming in from infinity to be absorbed-- like you say-- in the antenna. But that assumes that a very special boundary condition has been set up in the past, with the incoming wave approaching the antenna in just the right way. Consider now that a situation like the experiment you describe has been set up. I described the situation in my first paragraph in terms naturally described by retarded solutions; what happens if we consider the advanced solutions? It's the same as the antenna situation. Instead of the change in the field due to the added load at B propagating outward from B, a change in the field propagates *inward* to B and hits B just as the load is added, in such a way that the field afterward is a steady-state, continuous-wave situation. But you need very special boundary conditions set up in the past for that to happen; assuming that they're there is like expecting eggs to unscramble. The fact that we don't expect such boundary conditions in the past is a manifestation of the arrow of time, and opens up a whole other can of worms-- though I suspect that most arrows of time have something to do with *cosmological* boundary conditions. Therefore , it is the elementary interaction that is > fundamental , not the cause - effect relationship of emitter to absorber. I have no argument with that, except that I'd add that the boundary conditions necessary for a given solution are very important. I'd even say that the boundary conditions are what determine the cause-effect relationships. > In an ideal resonance condition most of the energy between coupled > elements is contained in a standing wave field that can be quantitatively > represented in terms of E (joules) or, more accurately VARS*t (volt amps > reactive*time). Are you in fact proposing that the entire system of A and B be placed in a box, so that the standing wave will occur? Or are A and B enormous plates, light-years wide in the case of interstellar communication? If they're small antennae placed on various planets, most of the energy will be contained in *traveling* waves, unless we introduce a boundary condition in which spherical wave fronts are perpetually moving inward toward the antennae from parts unknown, to interfere properly with the emitted waves. But that's actually irrelevant to what follows. > Changing the value of one of the reactive elements will > have an effect on the E or VAR*T value of this entire field which must be > compensated for by some equal and opposite reaction on the part of the > complementary reactive element at the other end. If energy is to be > conserved (according to the law of conservation of mass and energy) then > any delay in this reaction would result in consequences that are > mathematically unacceptable if the reactive elements continue to operate > during the delay. In other words, depending on the nature of the change > at a reactive element ,you end up with + or - value of VARS * T(delay) > which is either incompatible with conservation laws or ohm's law,(as > ohm's law is generically defined as Energy flow = Force / impediment to > force). On the other hand ,if the response at the other end is assumed to > be instantaneous , this conflict does NOT arise. You *are*, then, abandoning Maxwell's equations here in favor of something else. Since nobody is conspiring to set up favorable past boundary conditions to make the advanced solutions come out right, the change in the system has to be described by retarded solutions. The retarded solutions describe changes in the field propagating at a speed of c from the changes in the sources. There's no change from the continuous-wave situation at A until the change in the field arrives there. Energy starts to flow out of the field near B before it starts to flow into the field from A; conservation is ensured by a loss in the energy content of the field. Which of the myriad forms of the generalized Ohm's law are you actually using? If you're using V = I/z, keep in mind that the (complex) voltage across the reactance at B is the one you should use to compute the current through B. That is not at all necessarily the same as the voltage across A. It may be that Ohm's law doesn't explicitly include a time or distance allowance, but it obviously doesn't allow you to calculate the current through some element in a system by measuring the voltage across some totally different element. If you assume that the two voltages are always the same, then that's where you're abandoning Maxwell. If you then use the dot product of voltage and current phasors to find the power turned to heat, keep in mind once again that the voltage and current you should use are the voltage across and the current through the reacting element at B. To use anything else is just as unwarranted as measuring the voltage across my terminal's electrical cord and the current through power lines in Omaha and expecting the product to mean something. > Inasmuch as Maxwell's equations correctly predict phenomena , I have no > argument that they are not fundamental to that branch of electrodynamics > concerned with those phenomena. I am not aware of any attempt to apply > Maxwell's equations to resonance conditions (where doing so would not > have the consequences outlined above). You might want to read volume 2 of the Feynman lectures; he applies Maxwell's equations to cavity oscillations, albeit in a single, very idealized situation. It's clear in that case that what I've described would happen if the absorber/emitter (in this case, the wall of the cavity) were changed at some point, since what I've said about boundary conditions and changes in the field still applies there. > As far as Ohm's law is concerned , > it is emphasized that we're generalizing the meaning to a fundamental > function that is applicable to many different phenomena, for example: > I=V/r , I=V/z , flow=pressure/restriction , work=force/load.. etc. That's fine... see my concerns above. > I'm not sure by whose standards you are applying the term ``usual''.By > my own standards and others who work with actual electronic components it > would be unusual to do design calculations starting with Maxwell's > equations on through their formulaic derivations (although I'm sure > that's possible) . It's simply that we've learned to get by with standard > formulas that may be (or may not be , for all I know) derivable from > Maxwell. I know of no derivation from Maxwell's equations that are in > basic conflict with the generalized form of ohm's law, above. Of course, it would be very difficult to work with electronic components using nothing but Maxwell's equations; for active components using quantum-mechanical effects, it wouldn't even be possible. In this case, I'm not sure whether there really is a conflict between Maxwell and generalized-Ohm, and I'm not sure whether the rules you used really imply the results you claim. The AC version of Ohm's law, in which the reactance appears, only applies to situations in which the quantities all refer to the same circuit element, and to elements small enough that the time scale on which events are under consideration is much longer than the time it takes for transient effects like those of a sudden change in the reactance to die down. In this case, the elements that satisfy those criteria are the objects A and B, not the whole system. If you apply Ohm's law correctly, I think you'll find that it doesn't say anything about instantaneous transfer of energy. I *do* believe that Maxwell's equations don't imply the results you claim. At any rate, it's always good to be aware of the limits of the assumptions used to derive formulae. -- Matt McIrvin, professional gradgrind, amateur Usenet drifter
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Path: arc1-ca.pugleaf.net!sparky!uunet!gatech!rpi!uwm.edu!ogicse!das-news.harvard.edu!husc-news.harvard.edu!husc8!mcirvin From: mcirvin@husc8.harvard.edu (Mcirvin) Newsgroups: sci.physics Subject: Re: snarfy's reply to McIrvin Keywords: Maxwell vs. Ohm Message-ID: <mcirvin.713582409@husc8> Date: 12 Aug 92 01:20:09 GMT Article-I.D.: husc8.mcirvin.713582409 References: <4011@cruzio.santa-cruz.ca.us> Lines: 198 Nntp-Posting-Host: husc8.harvard.edu