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On Apr 26, 2:18 pm, Loui...@edu.herlufsholm.dk wrote:
> PIONEER ANOMALY AND COSMIC DECREASE OF GRAVITY
> The modified Hubble-law
>
> By Louis Nielsenhttp://www.rostra.dk/louis
>
> THE PIONEER-ANOMALY.
> When all known forces acting on the Pioneer spacecrafts are taken into
> consideration, a very small but unexplained force remains. It appears
> to cause a constant sunward acceleration for both spacecraft.
> It is observed that the Pioneer spacecrafts has a negative
> acceleration-anomaly about
> a(anomaly) = 8*10^(-10) m/s^2.
>
> COSMIC DECREASE OF GRAVITY. THE MODIFIED HUBBLE-LAW.
> In the following considerations about a modified Hubble-law where the
> Hubble-function H(T) is determined by a decreasing gravitational
> ‘constant’ G according to the relation:
>
> (1)  H(T) = - (dG/dT)*(1/G) = (1/3)*(1/T)
>
> In equation (1) (dG/dT) is the time derivative of the variable
> decreasing gravitational ‘constant’ G and T is the actual age of the
> Universe.
> The mathematical connection between H(T) and T gives a hyperbola
> curve.
>
> The modified Hubble-law is given by:
>
> (2)  v(T) = H(T)*D(T)
>
> In equation (2) v(T) is the radial velocity of an object at the time T
> the actual age of the Universe and D(T) is the distance from an
> observer to the object at the time T.
>
> By differentiation of the velocity in equation (2) we get the
> acceleration a(T) of the object at the time T when it is in a distance
> D(T). We get:
>
> (3)  a(T) = (- 2/9)* (D(T)/T^2)
>
> From equation (3) we see that the acceleration a(T) is negative. The
> velocity v(T) of the object is decreasing.
>
> We can rewrite equation (3) so we have a relationship between a(T),
> v(T) and T. We get:
>
> (4)  a(T) = (-2/3)* (v(T)/T)
>
> From equation (4) we see that the negative acceleration, the
> deceleration, of a given object is inversely proportional to the
> actual age T of the Universe and directly proportional to the actual
> velocity v(T).
>
> If T = 13*10^9 years = 4.1*10^17 sec and v(T) = 1*10^7 m/s (greater
> than the real velocity) then we get a very small value for the
> acceleration a(T) given by:
>
> (5)   a(T) = - 0.2*10^(-10) m/s^2
>
> The value in (5) is of the order of the measured acceleration-anomaly.
>
> Is the observed acceleration-anomaly of the Pioneer Probes caused by a
> cosmic decrease of the gravitational ‘constant’ and maybe explained by
> the above considerations?
>
> Best regards
> Louis Nielsen
> Denmarkhttp://www.rostra.dk/louis

Larger gravity.