🚀 go-pugleaf

On Sep 30, 1:43 am, frankli...@yahoo.com wrote:
> On Sep 29, 1:16 pm, Loui...@edu.herlufsholm.dk wrote:
>
>
>
>
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> >        Interpretation of E = m*c^2 as kinetic energies of sub-
> > particles.
>
> > By Louis Nielsen,   Treatise:http://www.rostra.dk/louis
>
> > What is the physical interpretation of Einstein's equation E = m*c^2
> > where E is the latent energy inside a portion of matter with the mass
> > m and where c is the velocity of light?
>
> > In my treatise I show that m*c^2 is equal to the total kinetic
> > energies of the sub-particles I call Unitons and of which all matter
> > consists.
>
> > The Uniton Postulate:
> > The unitons are the smallest and most fundamental energy-/matter
> > quanta in the Universe.
> > All matter consists of unitons and all interactions in the Universe
> > are consequences of
> > interacting unitons.
>
> > In my treatise I show that the total latent energy E inside a given
> > amount of matter with mass m is given by E = m*c^2 where c is the
> > velocity of light. And the expression m*c^2 is a measure of the TOTAL
> > KINETIC ENERGY OF THE UNITONS of which the matter consists.
> > Kinetic energy is the most fundamental form of energy.
>
> > By the above recognition of our physical world it is not difficult to
> > understand that all matter,
> > regardless of its chemical appearance contains energy as given by
> > Einstein's famous equation.
>
> > Read more in section 13 and section 14 of my treatise:  http://www.rostra.dk/louis
>
> > Best regards
> > Louis Nielsen
> > Denmark
>
> It's actually a lot easier than that. E=mc^2 because it is the sum of
> the kinetic energies of the particles ejected during pair production
> of a positron and electron. E = 1/2 mv^2 + 1/2 mv^2 = mv^2 where v=c
> and m = mass of positron and electron.
>
> See: What Does E=mc^2 Really Mean?
>
> http://www.geocities.com/franklinhu/emc.html
>
> fhuemc- Hide quoted text -
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> - Show quoted text -

You do understand that you are using the wrong relativistic formula
for kinetic energy?