🚀 go-pugleaf

On Jul 30, 6:46?pm, Loui...@edu.herlufsholm.dk wrote:
> The Accelerating Universe and Decreasing Cosmic
> Gravity.
>
>  By Louis Nielsen, Denmark    http://www.rostra.dk/louis
>
> The discovery of the accelerating Universe could be an indication of a
> cosmic decreasing gravity.
> Observations of supernovae, belonging to distant galaxies, show that
> they are situated at distances that are greater than what would be
> expected according to current cosmological models.
> This must mean that the galaxies in question have moved faster than
> expected. The analysis of the observations shows that the rate of
> expansion of the Universe appears to vary with position. More distant
> objects are receding from us faster than nearby ones. That is, the
> expansion of the Universe was faster at earlier times than it is right
> now.
>
> To save the traditional cosmological models the scientists now try to
> introduce different solutions, supported by new and old effects, such
> as 'dark energy', 'dark-matter' and the re-introduction of the
> 'cosmological constant' in Einstein's general field equations, etc.
>
> Decrease of the Cosmic Gravity.
> But maybe the accelerated expansion of the Universe is an indication
> of a cosmic decrease of Newton's gravitational 'constant'.
> In my considerations about "Quantum Cosmology with Decreasing Gravity"
> I assume that Newton's
> gravitational 'constant' G is a decreasing quantity. (Read more in my
> treatise).
>
> The decrease of G with cosmic time is (in the continuous
> approximation) given by the equation:
>
> (1)   (1/G)*(dG/dT) = - (1/3)*(1/T)   (dG/dT is the time derivative)
>
> In equation (1) T is the actual age of the Universe. We note that G
> does not decrease linearly with the age of the Universe. The relative
> decrease of G had been faster when the Universe was younger. When the
> Universe came into being, during the first cosmic quantum time
> intervals, G decreased extremely fast, corresponding to what in the
> standard cosmological theory is called an 'inflation phase'. In our
> epoch G decreases very slowly, so slow that it has not hitherto been
> possible to measure directly.
> If we could measure the relative decrease of G with very high
> precision then the age of the Universe can be calculated from equation
> (1).
> Due to a decrease of the cosmic gravitational forces, the distance
> between two gravitating mass systems - for example two galaxies will
> increase as the Universe ages.
>
> As the relative decrease of Newton's gravitational 'constant' is not a
> linearly function of time, this is also not the case for the increase
> in distance between two gravitational attracting systems.
>
> We can assume that the variable Hubble parameter H has connection to
> the decreasing gravitational 'constant' G according to the relation:
>
> (2)   H = - (1/G)*(dG/dT) = (1/3)* (1/T)
>
> The radial velocity v of an object is then given by the modified
> Hubble-relation:
>
> (3)   v = H*D = - (dG/dT)*(1/G)*D = (1/(3*T))*D
>
> In equation (3) D is the distance to the object. According to equation
> (3) v depends on both the distance D to the object and the actual age
> T of the Universe when the light was emitted.>From equation (3) we see that when T was smaller then v was higher.
>
> Therefore objects in the younger Universe had moved a greater distance
    If gravitylike everything else is quantized then what happens when
you get to a point where there may/maynot be a graviton>



 than calculated from the ordinary Hubble-relation.
>
> As our knowledge of the physical objects in the Universe is mainly
> obtained by analysis of the light emitted by the objects, it is also
> necessary to take into account the gravitational conditions when the
> light was emitted. For instance the gravitational shift of wavelength
> depends on the strength of the gravitational field in the position
> from which the light is emitted.
> Also other physical effects depend on the actual value of G.
>
> Best regards
> Louis Nielsen
> Denmark