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Article #15203

Re: Gradient of potential function of dynamic field

#15203
From: Bilge
Date: Sat, 06 Mar 2004 05:32
31 lines
2719 bytes
 Sergey Karavashkin: 
 >"Franz Heymann" <notfranz.heymann@btopenworld.com> wrote:
 
 >> If you think I am going to read any of all your recommended URL's, you are
 >> gravely mistaken.
 >> If you cannot understand that
 >> curl(grad(phi)) = 0, {Where phi is any scalar function of position)
 >> is a universal truth, then nothing more which you might have to say is
 >> useful except except to poke fun at.
 >> 
 >> Franz
 >
 >Pity you, Franz. You can think whatever, but if you don't see, where
 >to the gradient of potential in my animation is directed, it is really
 >useless for you to read all the rest. Spend your time among mushrooms.
 >;-)

  Only a complete nutcase would claim that he discovered a violation
of a mathematical identity.


  \nabla x (\nabla\Phi) = e_ijk \nabla_i\nabla_j\Phi

                        = \nabla_i\nabla_j\Phi - \nabla_j\nabla_i\Phi

                        = (\nabla_i\nabla_j - \nabla_j\nabla_i)\Phi

                        = 0

Tell me. What's next on the selflab agenda? Do you plan to show that
sin^2 + cos^2 != 1 for "dynamic fields"? 
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From: dubious@radioactivex.lebesque-al.net (Bilge)
Newsgroups: sci.physics,sci.physics.electromag,alt.sci.physics.new-theories,fj.sci.matter,sci.physics.relativity
Subject: Re: Gradient of potential function of dynamic field
Date: Sat, 06 Mar 2004 05:32:05 -0000
Organization: k lnOmega
Message-ID: <slrnc4itjl.64.dubious@radioactivex.lebesque-al.net>
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