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Equations, calculus, results, analysis

Where are the true scientists of sci.physics ?
They do not argue ?

Who want to continue in believing in "Michelson's experience" ?
No arguments ?
http://fr.babelfish.yahoo.com/translate_url?doit=done&tt=url&intl=1&fr=bf-home&trurl=http%3A%2F%2Fmonsyte.blogspot.com%2F2008%2F07%2Fles-miroirs-de-michelsonune-analyse.html&lp=fr_en&btnTrUrl=Traduire

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Equations, calculs, résultats, analyse

Où sont les vrais scientifiques de sci.physics ?
Ils n'argumentent pas ?

Qui veut continuer à croire à l' "expérience de Michelson" ?
Pas d'arguments ?
http://monsyte.blogspot.com/2008/07/les-miroirs-de-michelsonune-analyse.html
Yanick Toutain




On 20 juil, 21:31, Yanick Toutain <YanickTout...@gmail.com> wrote:
> http://fr.babelfish.yahoo.com/translate_url?doit=done&tt=url&intl=1&f...
> originalhttp://monsyte.blogspot.com/2008/07/les-miroirs-de-michelsonune-analy...
>
> MIRRORS OF MICHELSON: An analysis materialist
>
> An ANALYSIS MATERIALIST Of a PSEUDO RELATIVISTIC EXPERIMENT
> MIRRORS OF MICHELSON
>
> by Yanick Toutain
> Saturday July 19, 2008
> 19/07/08 21:08
>
> LANG=en
> ABSTRACT: The einsteinists swindlers off the relativity, frequently,
> show you has pseudo-experiment.
> They Tel. you again and again: it is the proof off the relativity.
> The experiment off Albert Michelson.
> With laser two rays with two different travels emitted.
> They say that the rays will arrives At the same place.
> They will arrives goal, yew there is year anisotropy off space, the
> different delays off the different rays will produce interference
> rays.
> Goal being unaware of Michelson didn' T know the speed off the sun: He
> was ignoramus that the sun travelled with has revolution speed: 250 km/
> s.
> He ignored what Herschel cuts understood: the sun cuts has relative
> motion 19.6 off km/s.
> Goal being unaware of relativists is unaware of the speed off the
> Galaxy: they is unaware of the speed off the Milky Way.
> Yew the speed off the Milky Way is 5000 km/s, the rays WILL NOT
> ARRIVES AT THE SAME PLACES!
>
> LANG=fr
> Two signals are emitted at the same time.
> They traverse two ways and meet at the end to form interference
> rings.
> One sees on the drawing of conclusion the points of impacts of the two
> photons:
>
> The green feature clearly figure the difference between the center of
> the final target and the place which the photon came to run up
> against.
> It is seen well that it does not touch the center of the target.
>
> One will see in lower part that
> longG = 1,143250689
> It is the difference between the point of impact and the center of the
> final target. (the sensor)
> As for the second photon, it made a longer way and thus, it comes to
> impact later, more than one billionth of seconds later, (1.00506E-09
> S)
> This time is sufficient so that the target moved.
> The center of the target is not any more at the same place.
> The dark green feature thus appears the difference between the center
> of the target (the sensor) (which is on y=2 X=11,42109233)
> and the point of impact of the second photon. (X=11,52488335
> Y=2,077843261)
> It is thus noted that the difference between the two photons, at the
> moment when they reach the target is equal to
> variation outdistances = 1,086383391 (m)
> How two photons (two luminous rays) which reaches two different places
> at two different moments could answer waitings, with the claims of
> Albert Michelson?
> The argument which it is about a description based on a device moving
> (fictitiously, for teaching reasons of visibility of graphics) with a
> third speed of light does not hold.
> If I use the assumption Ain Al Rami and that I suppose that the
> displacement of the Sun would be of 1/60° speed of light, I obtain the
> following results:
> variation time 1,00685E-11 S
> variation outdistances 0,226361982 m
> They come to impact with 22 centimetres one of the other and with a
> variation in the time of a hundredth of billionth of second.
> Variations of the points of impact compared to the center of the
> target-sensor
> longD 0,096945986 m
> longG 0,129375748 m
> With an absolute velocity of approximately 5000 kilometers a second,
> the first photon touches the target on the right, with 9 centimetres
> of the center.
> and the second, touches the target on the left, with 13 centimetres of
> the center.
> How do you imagine to obtain interference rings with similar such an
> absurd device?
> ========
> Detail
> All the graphs are made with an absolute translation of C/3 so that
> the details are visible.
> FIRST PHOTON
> IMPACT HAS
>
> As in point 0,0, a photon (yellow) is emitted.
> Its direction forms an angle alpha (36.87 degrees) compared to the
> absolute translation of the device. (milked yellow)
> To facilitate, it is seen that cosalpha=0.8 and sinalpha=0.6
> It moves towards the first mirror.
> This one forming an angle of 45 degrees compared to the device, it
> thus forms an angle of 36.87+45 degrees compared to the absolute
> translation. (cosalphap45 =0.1414 sinalphap45=0.9899)
> It will advance during
> your = 6,25433E-08 S
> {ta=3,41533E-08 S}
> For this length of time, the device moves in the vacuum at a speed S
> By arbitrary and teaching choice
> S = C/3
> {S = C/60 One has in this type of hooks the results with a speed of
> approximately 5000 kilometers a second. What the author calls the
> assumption Ain Al Rami and which must approximate our true speed in
> the vacuum}
> And thus
> S * your = 6,25 m
> {S * your = 0,170648464 m}
> The device and thus its center made a translation of 6.25 meters
> {17 centimetres. }
> It is the blue feature.
> One refers thus mauve to appear what the way of the photon would have
> been in the event of inertia: this mauve way moved during the
> displacement of the device.
> This mauve way connects the laser place of emission to the center of
> the central mirror.
> One sees well that the impact did not take place in the center, but at
> a distance
> longA 5,303300859 m
> {longA = 0,144800023 m}
> of this center.
> The impact takes place with 5.3 meters of the center of the first
> mirror.
> {14 centimetres}
> It is thus starting from this point of shifted impact that it is
> necessary to calculate the trajectory of this photon.
>
> IMPACT B
>
> One notices on this drawing that the way of the photon towards the
> second mirror is very short.
> It only lasts
> Tb = 3,47463E-09 S
> {Tb = 1,61749E-08 S}
> And the photon only traverses
> C Tb =1,041666667 m
> {C Tb =4,849119724 m}
> Indeed, it comes to run up against the second mirror far from the
> center of this one
> LongB = 3,472222222 m
> {longB = 0,037734149 m}
> Because during the time of the way since the impact has towards the
> impact B, the device (and thus the center of the second mirror has
> advanced
> S Tb = 0,347222222 m
> {S Tb =0,080818662 m}
> One sees the dark green feature which represents the difference
> between the center of the second mirror and the point of impact.
> This feature is directed according to an angle of alpha + 90 degrees
> compared to absolute advance.
> It is this orientation which justifies the brevity of the second way.
> IMPACT D
> (The letter C is neutralized in my texts to be strictly reserved for
> speed of light)
>
> This third impact of the first photon is thus the final shock on the
> target, on the sensor.
> It is the latter way which is supposed to form interference rings.
> (according to the project of Michelson)
> One thus sees the photon reconsidering his steps (in absolute space)
> ***
> It will move (milked yellow downwards)
> td = 4,16955E-08 S
> {td =3,36933E-08}
> and to traverse C td = 12.5 meters
> {C td = 10,1010101 m}
> But the target traversed
> S td = 4,166666667 m
> {S td = 0,168350168 m}
> The blue feature very clearly represents this projection of the center
> of the sensor.
> It thus will run up against the sensor against a distance
> longD= - 0,138888889
> It runs up against the sensor on the left center of this one.
> {longD = 0,096945986 Mr.
> He runs up, to C/60, the sensor on the right of the center}
> This low value strictly depends on the values on S, alpha, I, J, and L
> and can thus be much larger in certain provisions., If, for example,
> alpha = 53, the variation longD becomes equal to -2.27 Mr.
> {0,012 m smaller in this case}
> ========================
> SECOND PHOTON
> IMPACT E
>
> The photon which is emitted at the same time as the first will pass
> through the first mirror and will cross all the length of the device.
> It will run up against a mirror laid out with right angle of its
> trajectory. It is the orange feature in dotted line.
> Te = 6,8229E-08 S
> C you = 20,45454545 m
> It crossed more than 20 Mr.
> {you = 5,07108E-08 S
> C you =15,2027027 m
> It crossed more than 15,2 m}
> But, during this time, the device will have advanced
> S you =6,818181818 m
> {S you =0,253378378 m}
> It is the blue feature which appears this objective projection of the
> device in the vacuum.
> The mauve feature represents the distance between the central mirror
> and the center of the perpendicular mirror of the impact E.
> But the shock does not take place in the center.
> The green feature represents the difference between the center of the
> mirror E and the point of impact E.
> Skirt = 4,090909091 m
> {skirts = 0,152027027 m
> The curious and open materialist will notice the importance of this
> value: 15 centimetres.
> In this configuration, the impact takes place with more 15 centimetres
> of the center of this mirror.
> How much did the mirrors of Michelson measure?
> Did they let pass the photons to side?}
>
> IMPACT F
>
> There still, the photon reconsiders its steps. (milked orange
> continuous end)
> But it meets the central mirror which made a translation (in blue) of
> S tf = 0,20661157 m
> {S tf = 0,078957215 m}
> He will thus have traversed only
> C tf = 0,619834711 m
> {C tf =4,737432873 m}
> in a time
> tf = 2,06755E-09 S
> {tf = 1,58024E-08 S}
> It thus runs up against the central mirror against a distance from
> LongF = 5,96073485 m of its center. (milked green end)
> {longF = 0,281996102 m
> One sees here still whom the current configuration imposes of the
> mirrors broader than 29 centimetres. If not the photons pass to
> side! }
> IMPACT G
>
> The new orange feature into dotted appears the last section.
> Tg = 3,84219E-08 S
> longG = 1,143250689 m
> heureG = 1,08718E-07 S
> C tg = 11,51859504 m
> S tg = 3,83953168 m
>
> {tg = 1,75185E-08 S
> longG = 0,129375748 m
> heureG= 8,40317E-08 S
> C tg = 5,251920561 m
> S tg = 0,087532009 m}
>
> The photon runs up against the target against 1.14 meters of the
> center of this one.
> On the assumption Ain Al Rami, the shock takes place with 13
> centimetres on the left.
> IMPACT EFG and D
> One sees on this image the enormous difference between the
> trajectories of two photons (yellow and orange)
>
> The image of detail presented to the beginning proves to us that the
> difference between the two photons, at the time of the impacts is
> equal to
> variation ...
>
> plus de détails »