🚀 go-pugleaf

"Eric Gisse" <jowr.pi@gmail.com> wrote in message
news:d814f181-db22-409c-8df7-208e9d5ddbab@s12g2000prg.googlegroups.com...
> Max Keon wrote:
>> Eric Gisse wrote:
---
>>> The equations you are using are made up. They do not correspond to any
>>> standard physical theory, much less a well accepted one. The
>>> conclusions you derive from them that are incompatible with
>>> observation imply that _your made up equations_ are false, not the
>>> comparisons you draw between them and other theories.
>>
>> The results are the same as with GR. A clock fixed with the ECI
>> frame at an Earth surface radius loses 5.28e-10 seconds per
>> second of a GPS satellite radius clock. Multiply that by 86160
>>  = 4.55e-5 seconds per sidereal day. What's wrong with that?

> Are you unable to tell the difference between being a fair distance
> from a point mass to being immersed in an isotopic spray of matter?

>>  1+V/c^2 is the gravitational redshift factor, and that applies
>> to every electronic interaction, including clocks. V is GM/r. So
>> that becomes  1+(G*M/r)/c^2  which is the same as my equation
>>  t' = t+t*(G*M/r)/c^2  so long as "t" is specified as the time
>> unit, which is always 1.

> Your equation is wrong, as I already demonstrated.

My equation gives the correct answer.

>> The way it was written may have been confusing to you, but it
>> wasn't wrong.

> Actually, it is. You are taking the weak field approximation to GR,
> and then you apply it incorrectly.

But I get the right answer don't I.
---

>> You probably need to explain why everything in the early universe
>> was not gravitationally redshifted ENORMOUSLY, when GR, through
>> error, inadvertently predicts that it would be.

> What's the gravitational field from a point mass?
>
> Whats the gravitational field in an isotropic distribution of matter?
>
> If you think they are the same, you are stupid. If you think they are
> different, why are you arguing as if they were?

At the Earth's center of mass the gravitational field is
isotropic, but the field hasn't gone anywhere. An isotropic
gravity doesn't remove its consequences. Do you think it logical
that a clock enroute to the Earth center from a distance above
the surface, will continue to slow until it enters the body of
the Earth, then rather rapidly speed up until it's running as
fast as would a clock in deep space, where Earth's gravity is of
virtually no consequence? Do you really imagine that Earth's
gravity is of no more consequence to electronic interactions at
its center than in deep space? I have a bridge that may interest
you.

Dimension is still being shifted through everything at the center
of mass, in all directions at once. That's how the zero origin
universe works.

A clock tick rate won't further reduce once it has entered the
body of the Earth, nor will it speed up. What it was at the
surface will prevail right down to the center. Every electronic
interaction within the Earth remains redshifted as it would be
at the surface.

Compressing the Earth to half its diameter doubles the previous
clock slowing rate at the surface, and that redshift rate
prevails throughout the body.

So, shrinking the universe back to the era when it first became
transparent, when its temperature had reduced below 4000 K, is
going to produce an ENORMOUS gravitational redshift throughout
the body of the early universe. The CMBR started off with the
spectrum of a very cold blackbody radiator. Then it was
stretched.

Assuming that gravitational redshift is zero within the
isotropically distributed mass of the early universe will prove
to be fatal for the big bang theory.

This graph is according to your theories, showing no time loss
whatever for a clock at the Earth's center of mass.
 http://members.optusnet.com.au/maxkeon/erthclok.jpg
But the clock rate is very wrong according to mine.

The curves were generated according to Gauss's law, as applied
to gravity. M was determined thus,
 (new M) = (last M) / (previous radius / current radius) ^3
Is that all too much for you?

Proving that clocks don't speed up as radius shrinks within the
Earth is relatively simple.

One of two clocks synchronized at a depth below the Earth's
surface e.g. 6370000 meter radius, is shifted further into the
surface by 10000 meters, and they are both left running for some
time. The clock closest to the surface is then brought down to
the lower clock and compared.

I say they will both display the same elapsed time.

This is what you say.
For clocks at 6370000 and 6360000 radii:
 (new M) = 5.967e24 / (6370000 / 6360000) ^3 = 5.942e24 kg

 (G*(last M)/r)/c^2 = 6.9457e-10 m/sec^2
 (G*(new M)/r)/c^2 =  6.924e-10 m/sec^2

The difference is 2.17e-12 m/sec^2. Which is only 6.8e-5 seconds
per year. The difference is fairly minute, but it should be
detectable if it's there.
---

>>> Either way, the equations _YOU ARE MAKING UP_ have no relation to how
>>> general relativity actually treats the matter. In fact, the manifolds
>>> used to describe both Pound&Rebka and GPS _cannot_ describe the large
>>> scale structure and behavior of the universe.
>>
>> Surely the large scale structure and behavior of the universe
>> is only an extension of what is applicable around the Earth?

> No, idiot.

> ds^2 = -dt^2 + a(t)[dx^2 + dy^2 + dz^2] is the proper manifold to use
> for the early expanding universe. Stuff in a perfect fluid as a source
> in the field equations, and solve for a(t). This is done in most
> general relativity textbooks that cover cosmology.

You can confuse the issue with math jargon all you like, but so
long as I get the right answer, that's all that matters.

It's not your math that's at fault, it the theory that the math
is applied to that's wrong. i.e. The 4000 K blackbody spectrum
generated in the early universe was mandatorilly exactly what it
is today. But that would be impossible in the environment of the
early universe. Don't you think so?

-----

Max Keon