🚀 go-pugleaf

"Eric Gisse" <jowr.pi@gmail.com> wrote in message
news:a7476325-ebe0-458d-8e95-308d9602ce70@e4g2000hsg.googlegroups.com...
> On Jan 25, 1:53 pm, "Max Keon" <maxk...@optusnet.com.au> wrote:

> [snip junk]

You have my sympathy, but physics is the medium of truth and
truth will always prevail in the end.

> There is no point in discussing equations that you have simply MADE
> UP. So what if observation disagrees with your made up equations? It
> wouldn't be the first time.

Clock oscillators and the natural oscillators that generate
characteristic spectral lines have been proven to become
redshifted in a gravity well. Trying to explain the redshift as
lost energy due to a "photon's" climb from the well is absolutely
ridiculous.

The clocks of the GPS prove beyond doubt that they _physically_
run slower on the Earth's surface, and because clock and spectral
line oscillators behave in the same manner, it's not illogical
to assume that every other charge interaction will behave
likewise. That is, so long as it takes place outside a proton or
neutron. The oscillation rate in that case is blueshifted in a
gravity well, as demonstrated by Pound and Rebka.

The redshift rate in every interaction is fairly obviously
exactly the same as that in the interaction that provides the
tick rate for an atomic clock. They are all based on exactly
the same principle. The change rate is according to
 t' = t+t*(G*M/r)/c^2  where t is the time unit (= 1).

For an Earth surface radius, 6380000 meters, the redshifted 1
second for a clock that was previously unaffected by Earth's
gravity is 1.0000000006935 seconds. For a GPS satellite radius,
26570000 meters, the redshifted 1 second is 1.0000000001665
seconds.

If an atomic clock tick rate is 9192631770 hz on the surface, it
will be 1.0000000006935 / 1.0000000001665 = 1.000000000527,
 * 9192631770 = 9192631774.84 hz at the GPS radius. Spectral
lines and every other electronic interaction taken from the
surface to the GPS radius will be blueshifted by that same ratio.

Now take your electronic interactions within a black body
radiator environment back the gravity well of the early universe.
How redshifted do you think they would be?
Does, by nothing, seem logical to you?

>> This is how the CMBR compares with big bang's prediction. Error
>> bars won't help much here, will they.
>>
>>                    .
>>                 .     .
>>                .       . Actual CMBR
>>               .         .
>>             .             .
>>          .                   .
>>
>>        .......................... CMBR as predicted by
>>                                   the big bang theory.

> Both of these are wrong.
>
> The background radiation is blackbody.

Accurate ASCII black body radiator graphs are not all that easy
to draw you know. This one was generated according to Planck's
formula,  # = (8*pi*h*f^3)/(c^2*(EXP((h*f)/(k*t))-1))
 http://members.optusnet.com.au/maxkeon/bbcmbr.jpg
It demonstrates very clearly that the CMBR had to be generated
in the same environment as a 4000 K radiator today.
And that is just not possible.

Take note of what the big bang theory really predicts.

-----

Max Keon