🚀 go-pugleaf

On Jan 9, 6:42 pm, Eric Gisse <jowr...@gmail.com> wrote:
> On Jan 9, 5:35 am, mluttg...@wanadoo.fr wrote:
>
>
>
>
>
> > On Jan 8, 4:08 pm, Eric Gisse <jowr...@gmail.com> wrote:
>
> > > On Jan 8, 5:08 am, mluttg...@wanadoo.fr wrote:
>
> > > > On Jan 8, 11:13 am, Eric Gisse <jowr...@gmail.com> wrote:
>
> > > > > On Jan 8, 12:33 am, mluttg...@wanadoo.fr wrote:
>
> > > > > > On Jan 7, 10:29 pm, Eric Gisse <jowr...@gmail.com> wrote:
>
> > > > > > > On Jan 7, 6:18 am, mluttg...@wanadoo.fr wrote:
>
> > > > > > > > On Jan 7, 10:36 am, Eric Gisse <jowr...@gmail.com> wrote:
>
> > > > > > > > > On Jan 7, 12:02 am, mluttg...@wanadoo.fr wrote:
>
> > > > > > > > > > On Jan 6, 10:50 pm, "Ken S. Tucker" <dynam...@vianet.on.ca> wrote:
>
> > > > > > > > > > > On Jan 6, 2:00 am, mluttg...@wanadoo.fr wrote:
>
> > > > > > > > > > > > On Jan 6, 12:01 am, Dono <sa...@comcast.net> wrote:
>
> > > > > > > > > > > > > On Jan 5, 1:26 pm, mluttg...@wanadoo.fr wrote:
>
> > > > > > > > > > > > > > Let Nu0 the observed frequency at the bottom.
> > > > > > > > > > > > > > Assuming that m = hNu / c^2 represents the
> > > > > > > > > > > > > > photon's mass corresponding to the frequency Nu,
>
> > > > > > > > > > > > > Bad assumption, Marcel. Doesn't apply to the photon.
> > > > > > > > > > > > > It is nice seeing trying mainstream physics instead of your standard
> > > > > > > > > > > > > fare of pure crackpottery.
>
> > > > > > > > > > > > The proof of the pudding is in the eating:
> > > > > > > > > > > > With that assumption, one straightforwardly gets
>
> > > > > > > > > > > > E0 = E + mgd
> > > > > > > > > > > >      = hNu +  (hNu / c^2) * gd
> > > > > > > > > > > >      = hNu (1 + gd/c^2)
> > > > > > > > > > > >      = E (1 + gd/c^2)
>
> > > > > > > > > > > > This cannot be a mere coincidence.
>
> > > > > > > > > > > It's not coincidence, light energy,
> > > > > > > > > > > like all energy is subject to the
> > > > > > > > > > > Conservation of Energy, and is a
> > > > > > > > > > > cornerstone of General Relativity.
>
> > > > > > > > > > > > Marcel Luttgens
>
> > > > > > > > > > > Good work, regards
> > > > > > > > > > > Ken S. Tucker
>
> > > > > > > > > > Thank you.
>
> > > > > > > > > > I have added to my demonstration a justification of
> > > > > > > > > > the assumption that the mass m of a photon can be
> > > > > > > > > > expressed by the relation m = E / c^2 = hNu / c^2:
>
> > > > > > > > > Wrong by many orders of magnitude.
>
> > > > > > > > The mass E/c^2 has nothing to do with the photon
> > > > > > > > rest mass!
>
> > > > > > Of course, I mean the *hypothetical* photon rest mass!
>
> > > > > Do I have to post the particle data group link again? The hypothesis
> > > > > is wrong.
>
> > > > > > This precision is for Dono the Pencil.
>
> > > > > > > Idiot again. The formula E = mc^2 is only true at rest.
>
> > > > > > Now, according to Gisse, c is not a velocity!
>
> > > > > Idiot n+1 for some staggeringly huge n.
>
> > > > > The formula E = mc^2 is only true at rest since it is a special case
> > > > > of the general formula E^2 = [mc^2]^2 + [pc]^2.
>
> > > > > Since your [latest] amazingly stupid vocalized thought shows you have
> > > > > no idea where E = mc^2 comes from, I'll derive it for you.
>
> > > > > The four momentum of a massive particle is p^u = mU^u = (E, p) where p
> > > > > is the typical 3-momentum and U^u is the particle's four velocity. A
> > > > > massive particle has a squared four-velocity of -1.
>
> > > > > Form the scalar product of p^u.
>
> > > > > |p|^2 = g_uv p^u p^v = -E^2 + p^2 = - m^2 g_uv U^u U^v = - m^2
>
> > > > > E^2 = m^2 + p^2
>
> > > > > I purposefully worked in geometric units just to give you something to
> > > > > complain about.
>
> > > > > Now, Marcel, even you should know this one - what is the momentum of a
> > > > > particle that is not moving? What does E^2 = m^2 + p^2 reduce to for p
> > > > > = 0?
>
> > > > You are a physical ignoramus.
> > > > A photon is not a massive particle.
>
> > > Then m = 0.
>
> > > Gosh, that was hard.
>
> > > Do you need me to plug m = 0 into the formula for you, or can you
> > > figure it out yourself this time?
>
> > > > > > Instead of uttering stupidities, you should better
> > > > > > recognize that the combination of E = mc^2 with E = hNu
> > > > > > straightforwardly expains the result of the Pound
> > > > > > & Rebka experiment.
>
> > > > > Idiot n+2. Special relativity can not and does not describe
> > > > > gravitation.
>
> > > > > I will, however, entertain your delusion and request a derivation of
> > > > > gravitational redshift using only E = mc^2 and E = h\nu.
>
> > > > > > Gisse, you are acting like a true crackpot.
>
> > > > > No, I'm only acting like I know more about this subject than you.
> > > > > Which has the virtue of being true.
>
> > > > You are suffering from delusions.
>
> > > > Assuming that m = hNu / c^2 represents the
> > > > photon's mass corresponding to the frequency Nu, etc.
>
> > > Didn't you JUST SAY the photon is not a massive particle?
>
> > > > Such assumption is amply justified by the experimental
> > > > fact that "The energy of a system that emits a photon is
> > > > decreased by the energy E of the photon as measured
> > > > in the rest frame of the emitting system, which may result
> > > > in a reduction in mass in the amount E / c2. Similarly,
> > > > the mass of a system that absorbs a photon is increased
> > > > by a corresponding amount."
> > > > (cf.http://en.wikipedia.org/wiki/Photon#Physical_properties)
>
> > > > And realize that with such assumption,
>
> > > > E0 = E + mgd
>
> > > You are using Newtonian gravity with a quantum mechanical particle.
> > > Delightful.
>
> > > Newtonian gravity has been proven to be wrong - repeatedly.
> > > Furthermore, PHOTONS ARE MASSLESS. They can not be treated as if they
> > > were massive.
>
> > > >      = hNu +  (hNu / c^2) * gd
> > > >      = hNu (1 + gd/c^2)
> > > >      = E (1 + gd/c^2) , or
> > > > Nu0 = Nu (1 + gd/c^2)
>
> > > > Note that
> > > > gd/c^2 = 9.81 * 22.5 / 9E16
> > > >            =~ 2.5E-15,
> > > > which is the result of the Pound & Rebka experiment.
>
> > > > GR is not needed. And no clock rate is modified
> > > > (unless you consider a light emitter as a clock).
> > > > Only the frequency changes as a function of the height.
>
> > > > But, as a true crackpot, you are unable to understand this.
>
> > > No, as someone who actually has studied physics, it is crap. You just
> > > whined that photons have no mass, then you assume they do anyway.
>
> > Photons have no *rest* mass, but to their energy E = hNu
> > corresponds a (pseudo if you prefer) mass m = E/c^2.
>
> No, again. The formula E = mc^2 is _only true at rest_ or in a co-
> moving frame.
>
> I repeat, since you aren't getting it:
>
> E=mc^2 is only true if the particle is not moving.

You are more clever than Baez:

http://math.ucr.edu/home/baez/physics/Relativity/SR/light_mass.html

What is the meaning of the equation E=mc2?
You can interpret it to mean that energy is the same
thing as mass except for a conversion factor equal
to the square of the speed of light.  Then wherever there
is mass there is energy and wherever there is energy
there is mass. In that case photons have mass,
but we call it relativistic mass.

http://www.bio.net/bionet/mm/photosyn/1994-September/000439.html
Photon Mass?
Wei-Zhong He wzh at rio2.Berkeley.EDU
Sat Sep 10 23:31:03 EST 1994

Let's start with Einstein's equation:
	E = mc^2
This implies that anything with energy should
have mass, too.
For a photon, E=hv, where v is the frequency
of light. Therefore, we have
	m = hv/c^2
To clear a bit of confusion, m is the relativity
mass here.


> > > You
> > > want to mix SR and Newtonian gravitation, despite it being completely
> > > stupid. You then conclude, because in one instance Newton and GR
> > > agree, that "GR is not needed" despite a litany of evidence that
> > > disagrees with Newton.
>
> > I said and demonstrated that GR is not needed to explain
> > the P&R result.
>
> Too bad you are doing it in an inconsistent fashion.
>
> SR is valid only locally. Gravitation, by definition, is affecting
> light so SR cannot be used.
>
> Photons are massless, and massless particles are not treated very well
> by Newton.
>
> Plus, who the fuck cares? You found correspondence between Newton and
> GR at some limit, which is well known and expected. Now explain
> gravitational lensing without GR.
>
>
>
> > Btw, the formula E = mc^2 was known before Einstein,
> > so I don't mix SR and Newton.
>
> Provide a citation for it being known before Einstein, if you can.

Yes I can, but it would be a waste of time.

Bye,

Marcel Luttgens