🚀 go-pugleaf

On Sat, 05 Jan 2008 04:57:44 GMT, "hanson" <hanson@quick.net> wrote:

>
>"John C. Polasek" <jpolasek@cfl.rr.com> wrote in message
>news:atutn3l8ceqbc38v4v6on8jeumsl2di3fc@4ax.com...
>> On Fri, 04 Jan 2008 22:42:29 GMT, "hanson" <hanson@quick.net> wrote:
>>
>>>"Eric Gisse" <jowr.pi@gmail.com> wrote in message
>>>news:30d40ddf-3af0-4765-9287-ca83ba2b25a5@i29g2000prf.googlegroups.com...
>>>>
snip
>>>[hanson]
>>>It is not very clear what Potential *energy* Eric is talking about
>>>and for that matter what force. When I look at Eric's equation of
>>>Potential energy = GM/r where presumably G = L^3*M^-1*T^-2
>>>then Eric's Potential energy becomes a phenomenon, an event,
>>>with the dimension of L^2/T^2, a squared velocity, which is as
>>>mysterious as are  Keon's "y-rays"... but both of which appear
>>>to produce a mutual benefit for the mysterious term of "idiot".
>>>Thanks for the laughs, guys... ahahahaha... ahahahanson
>>>
>[John C. Polasek]
>> I'll just add this so you don't make such an ass of yourself.
>> The potential energy MG/4 is equal to V^2/2 terminal velocity if
>> dropped from infinity to R.
>> John Polasek
>>
>[hanson]
>.... ahahahahaha... But John, it is not clear here who that "you"
>really is, because **energy**, potential of otherwise, is defined
>as a dimensional identify of M*L^2/T^2 and hence MG/(4 or n)
>will have the dimension of M * L^3*M^-1*T^-2 = L^3/T^2 which
>is NOT any velocity^2. --- v^2 has a L^2/T^2 dimension.
>>
snip
I sent this message before, but don't see it now. 
MG/r is potential expressed as energy per unit mass.
MG/r^2 = acceleration or  LT^-2. Multiply by L
L*MG/r^2 = L^2T^-2 or velocity squared. 
Use a unit mass to get joules.
John Polasek