🚀 go-pugleaf

Ronn Blankenship wrote:
}
} However, the lab experiments involving annihilation of particles are
} pretty exact.  The gamma-ray spectrum of a radioactive isotope that is a
} positron emitter shows a sharp peak at .511 MeV, which is the energy
} equivalent of the mass of an electron (which is the same as the mass of
} a positron, of course).  When the positron is emitted from the nucleus,
} it rapidly encounters an electron, and the total mass of the two
} particles is turned into a pair of gamma rays, each with an energy of
} .511 Mev.  (Note that conservation of momentum requires that _two_ gamma
} rays be emitted.)


"Etherman" <etherman@mdc.net> writes:
>
>Quick question.  What happens to the energy in the EM fields of the
>e- and e+ after annihilation?

 It is part of the rest energy of those particles, and appears 
 in the photons.

 Note followups. 

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