🚀 go-pugleaf

Ramsay writes:

"I did not write "because the missing factor of 2..."; I've even
checked my files to see whether I wrote such a thing, and it isn't
there. You just tacked that onto my comment. Please do not misquote me
in the future- especially within quotation marks!"

Ramsay - look again at the text. I quoted you correctly , and then I gave
my version in contrast as an answer to your version.  I did not tack on
"missing factor of 2" to your statement - that was my statement!

You said that receiver will count partners of transmitter photons that were
not counted at transmitter and I challenged your remark by saying that the
receiver will not count them because the "missing factor of 2" occurs
equally for both receiver and transmitter - its an over-all factor for all
local probabilities.


I will comment of rest of your post later.

Someone wrote that commutativity of field operators across spacelike
intervals precludes ftl correlation signals. That is standard view but
it is false. See de la Torre in Foundations of Physics Letters - at
least two papers in last 2 years. I keep saying this but it passes
people by. Vanishing spacelike commutators are necessary if there
is no ftl correlation signal but not sufficient! Schrodinger showed
this in 1930!

You can have a Heisenberg uncertainty principle i.e. incompatibility
or product of root mean square fluctuations greater than non-zero
c-number even if the corresponding operators commute!  What does the
trick is entanglement! Because of nonlcoal entanglement, measurements
of commuting local operators outside each other's light cones can
interfere with each other!