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[Discussion of the usual heuristic explanation of Hawking radiation...]

Can anyone explain why extreme Reissner-Nordstrom black holes (Q=M) [or
charged Kerr solutions, L^2 + Q^2 = M^2] have a vanishing Hawking
temperature (T=0)?  The virtual-particle picture would make me erroneously
believe that positively-charged particles would spew out from the vicinity
of a positively-charged black hole.  My guess is that it has something to
do with the inner horizon (r-) going to zero.

[* This question is originally due to Dr. Stephen Hsu at Harvard *]

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